What is the smallest number that must be added to 45873 so that the sum is divisible by 11?
8
Dividing 45873 by 11, we get \(45873 = 11 \times 4170 + 3\), so the remainder is \(3\).
To make the number exactly divisible by 11, we need to add \(11 - 3 = 8\) to it.
Checking: \(45873 + 8 = 45881\), and \(45881 \div 11 = 4171\), which is exact.
Hence, the smallest number to be added is 8.
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