What is the ratio of interior angle to exterior angle of a regular polygon of n sides?
Let's break down how to find the ratio of the interior angle to the exterior angle in a regular polygon with 'n' sides. Regular polygons have equal side lengths and equal angle measures.
First, we need to recall the formulas for the interior and exterior angles of a regular polygon.
The sum of the interior angles of a polygon with 'n' sides is given by the formula: \((n-2) \times 180^\circ\). Since a regular polygon has 'n' equal interior angles, the measure of one interior angle is this sum divided by 'n'.
Measure of one interior angle \(= \frac{(n-2) \times 180^\circ}{n}\)
The sum of the exterior angles of any convex polygon is always \(360^\circ\). For a regular polygon, all exterior angles are equal. Thus, the measure of one exterior angle is \(360^\circ\) divided by the number of sides, 'n'.
Measure of one exterior angle \(= \frac{360^\circ}{n}\)
Now, we need to find the ratio of the interior angle to the exterior angle. We divide the measure of the interior angle by the measure of the exterior angle:
Ratio \(= \frac{\text{Interior Angle}}{\text{Exterior Angle}} = \frac{\frac{(n-2) \times 180^\circ}{n}}{\frac{360^\circ}{n}}\)
To simplify this complex fraction, we can multiply the numerator by the reciprocal of the denominator:
Ratio \(= \frac{(n-2) \times 180^\circ}{n} \times \frac{n}{360^\circ}\)
We can cancel 'n' from the numerator and denominator:
Ratio \(= \frac{(n-2) \times 180^\circ}{360^\circ}\)
Now, simplify the fraction \(\frac{180^\circ}{360^\circ}\), which is \(\frac{1}{2}\):
Ratio \(= (n-2) \times \frac{1}{2}\)
Ratio \(= \frac{n-2}{2}\)
This is the ratio of the interior angle to the exterior angle of a regular polygon with 'n' sides.
Let's look at the given options:
Our calculated ratio is \(\frac{n-2}{2}\), which matches Option 3.
| Angle Type | Formula (Regular n-sided polygon) |
|---|---|
| Sum of Interior Angles | \((n-2) \times 180^\circ\) |
| Measure of one Interior Angle | \(\frac{(n-2) \times 180^\circ}{n}\) |
| Sum of Exterior Angles | \(360^\circ\) |
| Measure of one Exterior Angle | \(\frac{360^\circ}{n}\) |
| Concept | Description / Formula | Application in this problem |
|---|---|---|
| Interior Angle Formula | \(\frac{(n-2)180^\circ}{n}\) for a regular n-gon | Used as the numerator in the ratio. |
| Exterior Angle Formula | \(\frac{360^\circ}{n}\) for a regular n-gon | Used as the denominator in the ratio. |
| Ratio Calculation | Division of Interior Angle by Exterior Angle | \(\frac{\frac{(n-2)180}{n}}{\frac{360}{n}} = \frac{n-2}{2}\) |
The interior and exterior angles at any vertex of a polygon are supplementary, meaning they add up to \(180^\circ\). We can verify this using the formulas:
Interior Angle + Exterior Angle \(= \frac{(n-2)180^\circ}{n} + \frac{360^\circ}{n}\)
Combine the fractions:
\(= \frac{(n-2)180^\circ + 360^\circ}{n}\)
Distribute the \(180^\circ\):
\(= \frac{180^\circ n - 360^\circ + 360^\circ}{n}\)
The \(-360^\circ\) and \(+360^\circ\) cancel out:
\(= \frac{180^\circ n}{n}\)
Cancel 'n':
\(= 180^\circ\)
This confirms that the sum of the interior and exterior angles at a vertex is \(180^\circ\) for any polygon, regular or not. However, the specific formulas \(\frac{(n-2)180^\circ}{n}\) and \(\frac{360^\circ}{n}\) are only for regular polygons because all angles are equal.
If the quadrilateral has an inscribed circle, then the sum of a pair of opposite sides equals:
A square is inscribed in a right angled triangle with legs p and q and has a common right angle with triangle. The diagonal of the square is given by
ABCDA is a con-cyclic quadrilateral of a circle ABCD with radius r and centre at O. If AB is the diameter and CD is parallel and half of AB and if the circle completes one rotation about the centre O, then the locus of the middle point of CD is a circle of radius:
The diagonals of a rhombus are of length 20 cm and 48 cm. What is the length of a side of the rhombus?
The area of a regular hexagon of side ‘a’ is equal to
Two parallel sides of a trapezium are 29 cm and 21 cm. Non-parallel sides are equal and each is of length 8.5 cm. What is the area of the trapezium?
ABCD is a parallelogram. A circle through A, B and C intersects CD (produced) at E. Which of the following is/are correct ?
1. AE = AD
2. CD = DE
Select the correct answer using the code given below :
ABCD is a trapezium in which AB is parallel to DC. The vertices A, B, C and D pass through a circle. Which of the following are correct?
1. AD = BC
2. ∠A + ∠ C = 180°
3. ∠ A + ∠ D = 180°
Select the correct answer using the code given below :
ABCD is a cyclic quadrilateral. AB and DC when produced, meet in E. Which of the following statements is/are correct?
1. ΔEBC is similar to Δ EAD.
2. ∠CBE + ∠ DAE = 180°.
Select the correct answer using the code given below :
ABCD is a trapezium in which AB is parallel to DC and 2AB = 3DC. The diagonals AC and BD intersect at O. What is the ratio of the area of Δ AOB to that of Δ DOC?
The ratio between the length and breadth of a rectangular park is 3 : 2. If a man cycling along the boundary at the speed of 12 km per hour completes one round in 8 minutes, then the area of the park in square meter will be
The side of a rhombus is 26 cm. The length of one of its diagonals is 20 cm. The sum of the lengths of the diagonals of this rhombus is equal to the perimeter of a rectangle. If the difference between the length and breadth of the rectangle is 6 cm, then what is the area of the rectangle?
PQRS is a cyclic quadrilateral. If ∠P is 4 times ∠R, and ∠S is 3 times ∠Q, then the average of ∠Q and ∠R is:
ABCD is a trapezium in which AB || DC and DC is perpendicular to BC. If ∠DAB = 110°, then ∠ABC - ∠ADC =_____.
The adjacent angles of a rhombus are in the ratio of 3 : 6. The smallest angle of the rhombus is: