The adjacent angles of a rhombus are in the ratio of 3 : 6. The smallest angle of the rhombus is:
60°
The question asks us to find the smallest angle of a rhombus where the adjacent angles are in the ratio 3:6.
A key property of a rhombus is that its adjacent angles are supplementary. This means that the sum of any two adjacent angles in a rhombus is always \(180^\circ\).
Let the two adjacent angles of the rhombus be represented by \(3x\) and \(6x\), based on the given ratio of 3:6.
Since the adjacent angles are supplementary, we can write the equation:
\(3x + 6x = 180^\circ\)
Now, we solve for \(x\):
Now that we have the value of \(x\), we can find the measure of each adjacent angle:
So, the two adjacent angles of the rhombus are \(60^\circ\) and \(120^\circ\).
The angles of the rhombus are alternating between these two values because opposite angles in a rhombus are equal. Therefore, the four angles of the rhombus are \(60^\circ, 120^\circ, 60^\circ, 120^\circ\).
We are asked to find the smallest angle of the rhombus. Comparing the two angle measures we found, \(60^\circ\) and \(120^\circ\), the smallest angle is \(60^\circ\).
Let's verify that these angles are indeed adjacent and supplementary:
The smallest angle is \(60^\circ\).
| Property Used | Given Ratio | Setup | Solution for x | Adjacent Angles | Smallest Angle |
|---|---|---|---|---|---|
| Adjacent angles are supplementary (\(180^\circ\)) | 3 : 6 | \(3x + 6x = 180^\circ\) | \(9x = 180^\circ \implies x = 20^\circ\) | \(3x = 60^\circ\) \(6x = 120^\circ\) |
\(60^\circ\) |
| Property | Description |
|---|---|
| Sides | All four sides are equal in length. |
| Opposite Angles | Opposite angles are equal in measure. |
| Adjacent Angles | Adjacent angles are supplementary (sum to \(180^\circ\)). |
| Diagonals | Diagonals bisect each other at right angles (\(90^\circ\)). |
| Diagonals and Angles | Diagonals bisect the angles through which they pass. |
A rhombus is a special type of parallelogram. This means it inherits all the properties of a parallelogram, such as opposite sides being parallel and equal, and diagonals bisecting each other. However, a rhombus has additional unique properties, primarily concerning its sides and angles.
In any quadrilateral, the sum of all interior angles is \(360^\circ\). For a rhombus with angles \(A, B, C, D\), if angles A and B are adjacent, then \(A + B = 180^\circ\). Since opposite angles are equal, \(A=C\) and \(B=D\). So the angles are \(A, B, A, B\). The sum is \(A+B+A+B = 2(A+B)\). Since \(A+B=180^\circ\), the sum is \(2 \times 180^\circ = 360^\circ\), which holds true for all quadrilaterals.
In our case, the angles are \(60^\circ, 120^\circ, 60^\circ, 120^\circ\). The sum is \(60 + 120 + 60 + 120 = 360^\circ\).
Understanding the supplementary nature of adjacent angles is crucial for solving problems involving rhombus angles and ratios.
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