What is the length of a diagonal of a cube whose side is 3 cm?
3√3 cm
The question asks us to find the length of a diagonal of a cube given that its side length is 3 cm. A cube is a three-dimensional solid object bounded by six square faces, facets or sides, with three meeting at each vertex. When we talk about the diagonal of a cube, we usually mean the space diagonal, which connects two opposite vertices passing through the interior of the cube.
To find the length of the space diagonal of a cube, we can use a specific formula derived from the Pythagorean theorem. If the side length of the cube is denoted by 'a', the length of the space diagonal, often denoted by 'd', can be calculated using the formula:
\[d = a\sqrt{3}\]
Let's understand how this formula is derived. Consider a cube with side length 'a'.
The problem states that the side length of the cube is 3 cm. So, we have \(a = 3\) cm.
Using the formula for the space diagonal:
\[d = a\sqrt{3}\]
Substitute the value of 'a':
\[d = 3\sqrt{3} \text{ cm}\]
Therefore, the length of the diagonal of the cube with a side length of 3 cm is \(3\sqrt{3}\) cm.
| Property | Formula (side 'a') | Value (side 3 cm) |
|---|---|---|
| Side Length | a | 3 cm |
| Face Diagonal Length | \(a\sqrt{2}\) | \(3\sqrt{2}\) cm |
| Space Diagonal Length | \(a\sqrt{3}\) | \(3\sqrt{3}\) cm |
| Volume | \(a^3\) | \(3^3 = 27\text{ cm}^3\) |
| Surface Area | \(6a^2\) | \(6 \times 3^2 = 6 \times 9 = 54\text{ cm}^2\) |
Understanding the properties of a cube is fundamental in solid geometry. The cube is a special case of several geometric solids, including a rectangular prism, a square prism, and a parallelepiped. Its symmetry makes its calculations straightforward.
Knowing the relationship between the side length, face diagonal, and space diagonal using the Pythagorean theorem is a key concept for solving problems involving cubes and other rectangular solids.
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