What is the least value that must be assigned to A so that the number 717A0280 is divisible by 3?
2
Sum of the known digits of 717A0280 = \(7+1+7+0+2+8+0 = 25\).
Total digit sum = \(25 + A\), which must be divisible by 3.
The least value of A that makes \(25+A\) divisible by 3 is 2 (since \(25+2=27\)).
Hence, the correct answer is 2 (A).
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