What is the largest common divisor of the numbers 1026, 2268 and 2430?
54
To find the largest common divisor (GCD) of the numbers 1026, 2268, and 2430, we can use the method of prime factorization. The GCD is the product of the common prime factors, each raised to the lowest power it appears in any of the factorizations.
The largest common divisor, also known as the greatest common divisor (GCD) or highest common factor (HCF), of two or more non-zero integers is the largest positive integer that divides each of the integers without leaving a remainder.
Let's find the prime factors for each number:
We divide 1026 by the smallest prime numbers until we reach 1:
So, the prime factorization of 1026 is $2^1 \times 3^3 \times 19^1$.
We divide 2268 by the smallest prime numbers until we reach 1:
So, the prime factorization of 2268 is $2^2 \times 3^4 \times 7^1$.
We divide 2430 by the smallest prime numbers until we reach 1:
So, the prime factorization of 2430 is $2^1 \times 3^5 \times 5^1$.
Now, let's look at the prime factorizations of all three numbers:
The common prime factors are 2 and 3.
Let's find the lowest power for each common prime factor across the three numbers:
The GCD is the product of these common prime factors raised to their lowest powers:
GCD$(1026, 2268, 2430) = 2^1 \times 3^3 = 2 \times (3 \times 3 \times 3) = 2 \times 27 = 54$.
Thus, the largest common divisor of 1026, 2268, and 2430 is 54.
| Number | Prime Factorization |
|---|---|
| 1026 | $2^1 \times 3^3 \times 19^1$ |
| 2268 | $2^2 \times 3^4 \times 7^1$ |
| 2430 | $2^1 \times 3^5 \times 5^1$ |
| Common Factors (Lowest Power) | $2^1, 3^3$ |
| GCD | $2^1 \times 3^3 = 54$ |
Besides prime factorization, another common method to find the GCD is the Euclidean Algorithm. This method is generally more efficient for larger numbers.
The Euclidean Algorithm for two numbers works by repeatedly applying the division lemma:
For two positive integers $a$ and $b$ with $a > b$, GCD$(a, b)$ = GCD$(b, r)$, where $r$ is the remainder when $a$ is divided by $b$. The process continues until the remainder is 0. The last non-zero remainder is the GCD.
To find the GCD of three numbers (a, b, c), you can first find GCD(a, b) and then find the GCD of the result and c: GCD(a, b, c) = GCD(GCD(a, b), c).
Related to GCD is the Least Common Multiple (LCM). The LCM of two or more numbers is the smallest positive integer that is a multiple of all the numbers. For two numbers $a$ and $b$, LCM$(a, b) = \frac{|a \times b|}{\text{GCD}(a, b)}$. For multiple numbers, you can use prime factorization: the LCM is the product of all unique prime factors raised to their highest power.
What is the HCF of 36 and 198?
Choose the correct statement from the following.
What is the LCM of (8x3 + 80x2 + 200x) and (4x4 + 16x3 - 20x2)?
The product of the two numbers is 1500 and their HCF is 10. The number of such possible pairs is/are:
The LCM of x2 − 8x + 15 and x2 − 5x + 6 is:
Six bells begin to toll together and toll, respectively, at intervals of 3, 4, 6, 7, 8 and 12 seconds. After how many seconds, will they toll together again?
A and B are two prime numbers such that A > B and their LCM is 209. The value of A 2 - B is:
A and B are two prime numbers such that A > B and their LCM is 209. The value of B 2 – A is:
LCM of two number is 22 times their HCF. If one of the numbers is 132 and the sum of LCM and HCF is 276, then what is the other number?
What is the LCM of 3.6, 1.8 and 0.144?
The greatest three-digit number which is divisible by 14, 28, and 42 is:
What is the greatest number that will divide 209 and 347 leaving remainder 5 and 7 respectively?
A number is three times another number and their HCF is 8. What is the sum of the squares of the numbers?
The HCF of 2091, 3485 and 4879 is x. The sum of the digits of x is:
If three numbers are in ratio of 3 : 5 : 7 and their LCM is 2415, what is the difference between the second number and the first number?