The LCM of x2 − 8x + 15 and x2 − 5x + 6 is:
(x - 2) (x - 3) (x − 5)
To find the Least Common Multiple (LCM) of algebraic expressions, specifically polynomials in this case, we follow a process similar to finding the LCM of numbers. The key steps involve factoring each polynomial into its prime factors and then taking the highest power of each distinct factor present in any of the polynomials.
We need to factor the quadratic expression \(x^2 - 8x + 15\). We look for two numbers that multiply to the constant term (15) and add up to the coefficient of the middle term (-8). The numbers that satisfy these conditions are -3 and -5 (\((-3) \times (-5) = 15\); \((-3) + (-5) = -8\)).
So, the factored form is:
\(x^2 - 8x + 15 = (x - 3)(x - 5)\)
Next, we factor the quadratic expression \(x^2 - 5x + 6\). We look for two numbers that multiply to the constant term (6) and add up to the coefficient of the middle term (-5). The numbers that satisfy these conditions are -2 and -3 (\((-2) \times (-3) = 6\); \((-2) + (-3) = -5\)).
So, the factored form is:
\(x^2 - 5x + 6 = (x - 2)(x - 3)\)
Now we list the prime factors obtained from the factorisation of each polynomial:
The distinct factors appearing in either polynomial are \((x - 2)\), \((x - 3)\), and \((x - 5)\). We need to consider the highest power of each distinct factor present in either expression.
The LCM is the product of the highest powers of all the distinct factors:
LCM \(= (x - 2)^1 \times (x - 3)^1 \times (x - 5)^1\)
LCM \(= (x - 2)(x - 3)(x - 5)\)
| Polynomial | Factored Form | Factors |
|---|---|---|
| \(x^2 - 8x + 15\) | \((x - 3)(x - 5)\) | \((x - 3), (x - 5)\) |
| \(x^2 - 5x + 6\) | \((x - 2)(x - 3)\) | \((x - 2), (x - 3)\) |
Distinct factors are \((x - 2), (x - 3), (x - 5)\). Highest power for each is 1.
LCM \(= (x - 2)(x - 3)(x - 5)\)
The Least Common Multiple of \(x^2 - 8x + 15\) and \(x^2 - 5x + 6\) is \((x - 2)(x - 3)(x - 5)\).
| Concept | Description | Application to Polynomials |
|---|---|---|
| Factoring | Breaking down an expression into simpler expressions that multiply together to give the original expression. | Essential first step to identify the prime factors of each polynomial. |
| Prime Factor (of a polynomial) | A polynomial that cannot be factored further into polynomials of lower degree over a given field (usually real numbers for such problems). | Similar to prime numbers for integers. Examples: \((x-2), (x+1), (x^2+1)\). |
| LCM (Least Common Multiple) | The smallest expression that is a multiple of two or more given expressions. | Formed by taking the highest power of each distinct prime factor found in the given polynomials. |
Similar to integers, there is a relationship between the Greatest Common Divisor (GCD) or Highest Common Factor (HCF) and the LCM of polynomials. For two polynomials \(P(x)\) and \(Q(x)\), their product is equal to the product of their GCD and LCM:
\(P(x) \times Q(x) = \text{GCD}(P(x), Q(x)) \times \text{LCM}(P(x), Q(x))\)
In this case, the factors of \(x^2 - 8x + 15\) are \((x - 3)(x - 5)\) and the factors of \(x^2 - 5x + 6\) are \((x - 2)(x - 3)\).
The common factor is \((x - 3)\), so the GCD \(= (x - 3)\).
The LCM \(= (x - 2)(x - 3)(x - 5)\).
Let's verify the relationship:
While the expressions are related, note that \((x - 3)^2\) appears in the product \(P(x)Q(x)\), whereas in \(\text{GCD} \times \text{LCM}\), \((x-3)\) is in the GCD and \((x-3)\) is in the LCM, resulting in \((x-3)^2\). This relationship holds true, but requires careful handling of repeated factors and leading coefficients in some contexts (though typically simplified for basic problems like this one).
Understanding both LCM and GCD helps in simplifying algebraic fractions involving these polynomials.
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