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Question

What is the kinetic energy possessed by an object having mass 25 kg and moving with a uniform velocity of 2 m s⁻¹?

This question was previously asked in
RRB NTPC 2024 Undergraduate CBT 1 Question Paper (29-Aug-2025) (Shift 1)
The correct answer is

50 J

The kinetic energy (KE) of an object is given by the formula:

\( KE = \frac{1}{2}mv^2 \)

where:

  • \(m\) is the mass of the object (in kg)
  • \(v\) is the velocity of the object (in m/s)

In this problem, we are given:

  • \(m = 25 \, kg\)
  • \(v = 2 \, m/s\)

Substituting these values into the formula, we get:

\( KE = \frac{1}{2} \times 25 \, kg \times (2 \, m/s)^2 \)

\( KE = \frac{1}{2} \times 25 \, kg \times 4 \, m^2/s^2 \)

\( KE = 25 \times 2 \, kg \cdot m^2/s^2 \)

\( KE = 50 \, J \)

Therefore, the kinetic energy possessed by the object is 50 Joules (J).

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