What is the kinetic energy possessed by an object having mass 25 kg and moving with a uniform velocity of 2 m s⁻¹?
50 J
The kinetic energy (KE) of an object is given by the formula:
\( KE = \frac{1}{2}mv^2 \)
where:
- \(m\) is the mass of the object (in kg)
- \(v\) is the velocity of the object (in m/s)
In this problem, we are given:
- \(m = 25 \, kg\)
- \(v = 2 \, m/s\)
Substituting these values into the formula, we get:
\( KE = \frac{1}{2} \times 25 \, kg \times (2 \, m/s)^2 \)
\( KE = \frac{1}{2} \times 25 \, kg \times 4 \, m^2/s^2 \)
\( KE = 25 \times 2 \, kg \cdot m^2/s^2 \)
\( KE = 50 \, J \)
Therefore, the kinetic energy possessed by the object is 50 Joules (J).
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