The question asks for the Highest Common Factor (HCF) of three given polynomials:
To find the HCF, we need to factorize each polynomial completely and then identify the common factors.
This polynomial can be treated as a quadratic equation in terms of \(x^2\). Let \(u = x^2\). The expression becomes \(u^2 - 13uy^2 - 300y^4\). We need to find two terms whose product is \(-300y^4\) and whose sum is \(-13y^2\).
By trying factors of 300, we find that \(-25y^2\) and \(12y^2\) multiply to \(-300y^4\) and add up to \(-13y^2\).
So, we can rewrite the expression as:
\(u^2 - 25y^2u + 12y^2u - 300y^4\)
Factoring by grouping:
\(u(u - 25y^2) + 12y^2(u - 25y^2)\)
\((u + 12y^2)(u - 25y^2)\)
Substitute back \(u = x^2\):
\((x^2 + 12y^2)(x^2 - 25y^2)\)
The term \(x^2 - 25y^2\) is a difference of squares (\(a^2 - b^2 = (a-b)(a+b)\)), where \(a=x\) and \(b=5y\). So, \(x^2 - 25y^2 = (x - 5y)(x + 5y)\).
Therefore, the complete factorization of the first polynomial is:
\(P_1 = (x - 5y)(x + 5y)(x^2 + 12y^2)\)
Let's test if \((x - 5y)\) is a factor by substituting \(x = 5y\) into the polynomial:
\((5y)^3 - 4(5y)^2y - 4(5y)y^2 - 5y^3\)
\(= 125y^3 - 4(25y^2)y - 20y^3 - 5y^3\)
\(= 125y^3 - 100y^3 - 20y^3 - 5y^3\)
\(= 125y^3 - 125y^3 = 0\)
Since the result is 0, \((x - 5y)\) is indeed a factor. Now, we perform polynomial division to find the other factor.
Dividing \(x^3 - 4x^2y - 4xy^2 - 5y^3\) by \((x - 5y)\):
x^2 + xy + y^2 |
____________________ |
x - 5y | x^3 - 4x^2y - 4xy^2 - 5y^3 |
-(x^3 - 5x^2y) |
____________________ |
x^2y - 4xy^2 |
-(x^2y - 5xy^2) |
____________________ |
xy^2 - 5y^3 |
-(xy^2 - 5y^3) |
_____________ |
0 |
Thus, the factorization is:
\(P_2 = (x - 5y)(x^2 + xy + y^2)\)
This is a difference of cubes, \(a^3 - b^3\), where \(a = x\) and \(b = 5y\). The formula for the difference of cubes is \(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\).
Applying the formula:
\(P_3 = (x - 5y)(x^2 + x(5y) + (5y)^2)\)
\(P_3 = (x - 5y)(x^2 + 5xy + 25y^2)\)
Now, let's list the factors of each polynomial:
The common factor present in all three polynomials is \((x - 5y)\).
Therefore, the HCF of the three given polynomials is \(x - 5y\).
The HCF of \(x\) and \(y\) is \(H\). Consider the following statements in respect of the HCF of \(p=\frac{x^3 + y^3}{x^2-xy+y^2}\) and \(q=\frac{x^3-y^3}{x^2+xy+y^2}\) :
I. The HCF of \(p\) and \(q\) can be \(H\).
II. The HCF of \(p\) and \(q\) can be \(2H\).
Which of the statements given above is/are correct?
Let \(N\) be the least positive multiple of 11 that leaves a remainder of 5 when divided by 6, 12, 15, 18. Which one of he following is correct?
Let \(n\) be a natural number. The HCF of \(n, n + 10\) is 10. If the LCM is \(x\) (a 2-digit number), then how many values of \(x\) are possible?
Consider the following statements in respect of prime numbers p and q:
The HCF and LCM of two numbers are 12 and 72, respectively. If the ratio of the two numbers is 2 ∶ 3, then the larger of the two numbers is:
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Joseph visits the club on every 5 th day, Harsh visits on every 24 th day, while Sumit visits on every 9 th day. If all three of them met at the club on a Sunday, then on which day will all three of them meet again?
What is the least number which when divided by 12,20 and 24 leaves in each case a remainder of 8?
Which of the following is a pair of co-primes?