What is the geometric mean of 3, 9, 27, 81, 243, 729, 2187?
The geometric mean is a type of average that indicates the central tendency of a set of numbers by using the product of their values (as opposed to the arithmetic mean, which uses their sum). It is calculated by multiplying all the numbers in a set and then taking the n-th root of the product, where n is the count of numbers in the set.
The formula for the geometric mean (GM) of a set of n numbers (\(x_1, x_2, \dots, x_n\)) is:
\( GM = \sqrt[n]{x_1 \times x_2 \times \dots \times x_n} \)
The question asks for the geometric mean of the following sequence of numbers:
3, 9, 27, 81, 243, 729, 2187
First, let's count the numbers in the set. There are 7 numbers, so n = 7.
We can observe that these numbers are powers of 3:
Product = \(3^1 \times 3^2 \times 3^3 \times 3^4 \times 3^5 \times 3^6 \times 3^7\)
Using the exponent rule \(a^m \times a^n = a^{m+n}\), we add the exponents:
Product = \(3^{(1+2+3+4+5+6+7)}\)
Sum of exponents = \(\frac{7(7+1)}{2} = \frac{7 \times 8}{2} = \frac{56}{2} = 28\).
So, the product is \(3^{28}\).
\( GM = \sqrt[7]{3^{28}} \)
Using the exponent rule \(\sqrt[n]{a^m} = a^{m/n}\):
\( GM = 3^{28/7} \)
\( GM = 3^4 \)
\(3^4 = 3 \times 3 \times 3 \times 3 = 81\).
The geometric mean of the numbers 3, 9, 27, 81, 243, 729, and 2187 is 81.
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