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Question

What is the equation of the line which is equidistant from the lines \(2x - 4y - 7 = 0\) and \(6x - 12y + 1 = 0\)?

This question was previously asked in
NDA 2 2026 GAT Question Paper (13-Sep-2026)
The correct answer is

\(3x-6y-5=0\)

Writing both lines with matching coefficients of \(x\) and \(y\): \(6x-12y-21=0\) and \(6x-12y+1=0\). The line equidistant from two parallel lines \(ax+by+c_1=0\) and \(ax+by+c_2=0\) is \(ax+by+\dfrac{c_1+c_2}{2}=0\). This gives \(6x-12y-10=0\), which simplifies to \(3x-6y-5=0\).

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Similar Questions

  1. What is the sum of the intercepts of the line whose perpendicular distance from origin is 4 units and the angle which the normal makes with positive direction of x-axis is 15°?

  2. What is the acute angle between the lines represented by the equations \({\rm{y}} - \sqrt 3 {\rm{x}} - 5 = 0\) and \(\sqrt 3 {\rm{y}} - {\rm{x}} + 6 = 0\) ?

  3. Consider the following statements in respect of the line passing through origin and inclining at an angle of 75° with the positive direction of x-axis :

    1. The line passes through the point \(\left(1, \frac{1}{2−\sqrt{3}}\right)\) .

    2. The line entirely lies in first and third quadrants.

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Important Questions from Properties of Lines

  1. The slope of the line 4x + 3y - 4 = 0 is:

  2. Let x + 2y + 4 = 0 and -4x + 2y - 3 = 0 be the equations of two straight lines. Then

  3. If the slope of the line joining the points (k, 4) and (-3, -2) is \(\frac{1}{2}\), then the value of k is

  4. If the equation

    3x2 + 7xy + 2y2 + 5x + 5y + k = 0

    represents a pair of straight lines, then the value of k is

  5. If the sum of the slopes of the lines given by x2 - 2cxy - 7y2 = 0 is four time their products, then the value of c is

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