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Question

What compound is formed when dilute hydrochloric acid is added to a beaker containing a small amount of copper oxide?

This question was previously asked in
RRB NTPC 2024 Undergraduate CBT 1 Question Paper (29-Aug-2025) (Shift 1)
The correct answer is

Copper (II) Chloride

When dilute hydrochloric acid (HCl) is added to copper oxide (CuO), a chemical reaction occurs, forming copper (II) chloride (CuCl2) and water (H2O). The balanced chemical equation for this reaction is:

CuO + 2HCl → CuCl2 + H2O

Explanation:

  • Copper oxide is a basic oxide. It reacts with hydrochloric acid, which is an acid, to form a salt and water. This type of reaction is known as a neutralization reaction.
  • In this reaction, copper oxide provides Cu2+ ions, while hydrochloric acid provides Cl- ions.
  • The compound formed is copper (II) chloride, as the copper is in the +2 oxidation state.

Therefore, when dilute hydrochloric acid is added to copper oxide, the compound formed is Copper (II) Chloride.

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