I: BaCl\(_2\) (aq) + Na\(_2\)SO\(_4\) (aq) → BaSO\(_4\) (s) + 2NaCl (aq)
II: Pb(NO\(_3\))\(_2\) (aq) + KI (aq) → PbI\(_2\) (s) + 2KNO\(_3\)(aq)
Which of the following correctly classifies these reactions?
This solution classifies the provided chemical reactions, identifying them as double displacement reactions based on ion exchange.
Reaction I involves the interaction between Barium Chloride (BaCl$_2$) and Sodium Sulfate (Na$_2$SO$_4$) in an aqueous solution.
The chemical equation is: $BaCl$_2$ (aq) + Na$_2$SO$_4$ (aq) → BaSO$_4$ (s) + 2NaCl (aq)$
Reaction II describes the reaction between Lead(II) Nitrate (Pb(NO$_3$)$_2$) and Potassium Iodide (KI) in an aqueous medium.
The chemical equation is: $Pb(NO$_3$)$_2$ (aq) + 2KI (aq) → PbI$_2$ (s) + 2KNO$_3$(aq)$
Both Reaction I and Reaction II clearly demonstrate the characteristics of double displacement reactions. This involves the mutual exchange of ions between two ionic compounds dissolved in water. Therefore, both reactions are classified as double displacement reactions.
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