If we take a small amount of washing soda and add approximately 1 mL of dilute hydrochloric acid to it, what will we observe?
CO2 gas comes out with brisk effervescence.
Let's explore what happens when washing soda (sodium carbonate) reacts with dilute hydrochloric acid.
When an acid reacts with a carbonate, it typically produces a salt, water, and carbon dioxide gas. This is a classic type of reaction in chemistry.
The balanced chemical equation for the reaction between sodium carbonate and hydrochloric acid is:
\(\text{Na}_2\text{CO}_3\text{(aq)} + 2\text{HCl}\text{(aq)} \rightarrow 2\text{NaCl}\text{(aq)} + \text{H}_2\text{O}\text{(l)} + \text{CO}_2\text{(g)}\)
Based on the chemical equation, the products are:
The formation of carbon dioxide gas ($\text{CO}_2$) is easily observable. When $\text{CO}_2$ is produced rapidly in a liquid, it causes bubbles to form and rise. This rapid bubbling is called effervescence. Since the reaction between a strong acid like $\text{HCl}$ and a carbonate like $\text{Na}_2\text{CO}_3$ is vigorous, the effervescence is brisk.
Let's look at why the other options are incorrect:
Therefore, the correct observation is the release of $\text{CO}_2$ gas with brisk effervescence.
| Reactants | Products | Observable Sign of Gas | Name of Gas |
|---|---|---|---|
| Metal Carbonate (e.g., $\text{Na}_2\text{CO}_3$) + Acid (e.g., $\text{HCl}$) | Salt + Water + Carbon Dioxide ($\text{CO}_2$) | Brisk Effervescence (bubbling) | Carbon Dioxide ($\text{CO}_2$) |
| Metal Bicarbonate (e.g., $\text{NaHCO}_3$) + Acid (e.g., $\text{HCl}$) | Salt + Water + Carbon Dioxide ($\text{CO}_2$) | Brisk Effervescence (bubbling) | Carbon Dioxide ($\text{CO}_2$) |
| Metal + Acid (e.g., $\text{Zn}$ + $\text{HCl}$) | Salt + Hydrogen ($\text{H}_2$) | Bubbles, gas burns with 'pop' sound | Hydrogen ($\text{H}_2$) |
Effervescence: This term specifically describes the escape of gas dissolved in a liquid or produced during a reaction in solution. It's the visible bubbling you see, like in a fizzy drink.
Test for Carbon Dioxide ($\text{CO}_2$): The presence of carbon dioxide gas can be confirmed by passing the gas through lime water (a solution of calcium hydroxide, $\text{Ca(OH)}_2$). The lime water turns milky or cloudy due to the formation of insoluble calcium carbonate ($\text{CaCO}_3$).
\(\text{CO}_2\text{(g)} + \text{Ca(OH)}_2\text{(aq)} \rightarrow \text{CaCO}_3\text{(s)} + \text{H}_2\text{O}\text{(l)}\)
If excess carbon dioxide is passed, the milkiness disappears as the insoluble calcium carbonate converts to soluble calcium bicarbonate ($\text{Ca(HCO}_3\text{)}_2$).
\(\text{CaCO}_3\text{(s)} + \text{H}_2\text{O}\text{(l)} + \text{CO}_2\text{(g)} \rightarrow \text{Ca(HCO}_3\text{)}_2\text{(aq)}\)
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