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Question

Two students X and Y appeared in a test. The score of X is 20 more than that of Y. If the score of X is 75% of the sum of the scores of X and Y, then what is the ratio of score of X to score of Y?

This question was previously asked in
CDS 2 2025 Maths Question Paper (14-Sep-2025)
The correct answer is
3:1

Test Score Problem Analysis

This problem involves finding the ratio between the scores of two students, X and Y, based on given conditions relating their scores. We need to use algebra to solve for the unknown scores and their ratio.

  • Let \(S_X\) denote the score of student X.
  • Let \(S_Y\) denote the score of student Y.

Score Conditions Breakdown

The problem provides two key pieces of information that we can translate into mathematical equations:

  1. "The score of X is 20 more than that of Y." This translates to the equation:

    \(S_X = S_Y + 20\)

  2. "The score of X is 75% of the sum of the scores of X and Y." This translates to:

    \(S_X = 75\% \times (S_X + S_Y)\)

    To make calculations easier, we convert the percentage to a fraction:

    \(S_X = \frac{75}{100} \times (S_X + S_Y)\)

    Simplifying the fraction gives:

    \(S_X = \frac{3}{4} (S_X + S_Y)\)

Calculating the Ratio of Scores

The second equation gives us a direct relationship between \(S_X\) and \(S_Y\). Let's use it to find this relationship.

  1. Start with the equation derived from the percentage condition:

    \(S_X = \frac{3}{4} (S_X + S_Y)\)

  2. To eliminate the fraction, multiply both sides of the equation by 4:

    \(4 \times S_X = 3 \times (S_X + S_Y)\)

    Distribute the 3 on the right side:

    \(4S_X = 3S_X + 3S_Y\)

  3. Now, rearrange the terms to group \(S_X\) terms together. Subtract \(3S_X\) from both sides:

    \(4S_X - 3S_X = 3S_Y\)

    This simplifies to:

    \(S_X = 3S_Y\)

This equation, \(S_X = 3S_Y\), directly shows that the score of X is three times the score of Y. This means the ratio \(S_X : S_Y\) is \(3:1\).

Although we have found the ratio, we can use the first condition (\(S_X = S_Y + 20\)) to find the specific scores and verify our result.

  1. Substitute the relationship \(S_X = 3S_Y\) into the first equation:

    \(3S_Y = S_Y + 20\)

  2. Solve for \(S_Y\). Subtract \(S_Y\) from both sides:

    \(3S_Y - S_Y = 20\)

    \(2S_Y = 20\)

  3. Divide by 2:

    \(S_Y = \frac{20}{2}\)

    \(S_Y = 10\)

  4. Now, find \(S_X\) using the relationship \(S_X = 3S_Y\):

    \(S_X = 3 \times 10\)

    \(S_X = 30\)

So, student X scored 30 and student Y scored 10. Let's quickly check if these scores fit the original problem statements:

  • Is X's score (30) 20 more than Y's score (10)? Yes, \(30 = 10 + 20\).
  • Is X's score (30) 75% of the sum of scores (30 + 10 = 40)? Yes, \(0.75 \times 40 = 30\).

Both conditions are met.

Final Score Ratio Determination

The question asks for the ratio of the score of X to the score of Y, which is \(S_X : S_Y\).

Using the calculated scores, the ratio is \(30 : 10\).

To simplify the ratio, we divide both parts by their greatest common divisor, which is 10:

\(\frac{30}{10} : \frac{10}{10}\)

\(3 : 1\)

Alternatively, the relationship \(S_X = 3S_Y\) directly gives us the ratio \(3:1\).

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