This problem involves finding the ratio between the scores of two students, X and Y, based on given conditions relating their scores. We need to use algebra to solve for the unknown scores and their ratio.
The problem provides two key pieces of information that we can translate into mathematical equations:
\(S_X = S_Y + 20\)
\(S_X = 75\% \times (S_X + S_Y)\)
To make calculations easier, we convert the percentage to a fraction:
\(S_X = \frac{75}{100} \times (S_X + S_Y)\)
Simplifying the fraction gives:
\(S_X = \frac{3}{4} (S_X + S_Y)\)
The second equation gives us a direct relationship between \(S_X\) and \(S_Y\). Let's use it to find this relationship.
\(S_X = \frac{3}{4} (S_X + S_Y)\)
\(4 \times S_X = 3 \times (S_X + S_Y)\)
Distribute the 3 on the right side:
\(4S_X = 3S_X + 3S_Y\)
\(4S_X - 3S_X = 3S_Y\)
This simplifies to:
\(S_X = 3S_Y\)
This equation, \(S_X = 3S_Y\), directly shows that the score of X is three times the score of Y. This means the ratio \(S_X : S_Y\) is \(3:1\).
Although we have found the ratio, we can use the first condition (\(S_X = S_Y + 20\)) to find the specific scores and verify our result.
\(3S_Y = S_Y + 20\)
\(3S_Y - S_Y = 20\)
\(2S_Y = 20\)
\(S_Y = \frac{20}{2}\)
\(S_Y = 10\)
\(S_X = 3 \times 10\)
\(S_X = 30\)
So, student X scored 30 and student Y scored 10. Let's quickly check if these scores fit the original problem statements:
Both conditions are met.
The question asks for the ratio of the score of X to the score of Y, which is \(S_X : S_Y\).
Using the calculated scores, the ratio is \(30 : 10\).
To simplify the ratio, we divide both parts by their greatest common divisor, which is 10:
\(\frac{30}{10} : \frac{10}{10}\)
\(3 : 1\)
Alternatively, the relationship \(S_X = 3S_Y\) directly gives us the ratio \(3:1\).
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