This problem asks us to find the ratio between two expressions, \((a-b+c)\) and \((a+b-c)\), given the ratios of the sums of pairs of these variables. We are given that:
\( (a+b): (b+c): (c+a) = 5:7:6 \)
Our goal is to determine the value of the ratio \( (a-b+c):(a+b-c) \).
When dealing with ratios, it's helpful to introduce a constant, let's call it \(k\). We can rewrite the given proportions as equations:
To find the individual values of \(a\), \(b\), and \(c\), we can first add these three equations together:
\( (a+b) + (b+c) + (c+a) = 5k + 7k + 6k \)
Combining like terms, we get:
\( 2a + 2b + 2c = 18k \)
Factor out the 2:
\( 2(a+b+c) = 18k \)
Divide both sides by 2 to find the sum of all three variables:
\( a+b+c = 9k \)
Now, we can find the value of each variable by subtracting the sum of the other two variables from the total sum (\(a+b+c = 9k\)):
So, we have \(a=2k\), \(b=3k\), and \(c=4k\). These are the values of our variables in terms of the constant \(k\). Note that \(k\) cannot be zero, otherwise all sums would be zero, contradicting the given ratios.
Now we need to find the ratio \( (a-b+c):(a+b-c) \). Let's substitute the values we found for \(a\), \(b\), and \(c\):
Now, form the ratio:
\( (a-b+c):(a+b-c) = 3k : k \)
Since \(k\) is a non-zero constant, we can simplify this ratio by dividing both parts by \(k\):
\( 3k : k = 3:1 \)
The value of the ratio \( (a-b+c):(a+b-c) \) is \( 3:1 \).
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