Two students move identical boxes through a distance of 10 m. Student A applies a force of 50 N, while Student B applies a force of 100 N. What is the difference in the work done by the two students?
500 J
To solve the problem of determining the difference in work done by two students who apply different forces over the same distance, we use the formula for work:
\(W = F \times d\)
Where:
- \(W\) is the work done in joules (J).
- \(F\) is the force applied in newtons (N).
- \(d\) is the distance moved in meters (m).
Calculating the work done by each student:
- Work done by Student A:
Applying a force of 50 N over a distance of 10 m:
\(W_A = 50 \, \text{N} \times 10 \, \text{m} = 500 \, \text{J}\)
- Work done by Student B:
Applying a force of 100 N over the same distance of 10 m:
\(W_B = 100 \, \text{N} \times 10 \, \text{m} = 1000 \, \text{J}\)
Now, we calculate the difference in work done by Student A and Student B:
\(\text{Difference} = W_B - W_A = 1000 \, \text{J} - 500 \, \text{J} = 500 \, \text{J}\)
Therefore, the difference in the work done by the two students is 500 J, which matches the correct answer option.
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