A force of 10 newtons moves an object 2 metres. How much work is done?
20 joules
To determine the amount of work done, we need to use the formula for work, which is given by:
\(W = F \times d \times \cos(\theta)\)
where:
- \(W\) is the work done, measured in joules (J).
- \(F\) is the force applied, measured in newtons (N).
- \(d\) is the displacement, measured in meters (m).
- \(\theta\) is the angle between the force and displacement vectors.
In this problem, the angle \(\theta = 0^\circ\) because the force is applied in the direction of displacement. Therefore, \(\cos(\theta) = \cos(0^\circ) = 1\).
Given:
- Force \(F = 10 \, \text{N}\)
- Displacement \(d = 2 \, \text{m}\)
Substituting these values into the work formula:
\(W = 10 \times 2 \times 1 = 20 \, \text{J}\)
Therefore, the work done is 20 joules.
The correct answer is: 20 joules
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