Two identical bulbs are connected in parallel to a battery. If one bulb burns out, what happens to the brightness of the other bulb?
The brightness of the other bulb remains unchanged.
In a parallel circuit, each branch is connected directly across the battery, so each bulb experiences the full battery voltage independently of the other branch. The current through one branch does not depend on whether the other branch is intact.
If one of the two identical bulbs burns out, its branch simply becomes an open circuit and no current flows through it, but the remaining bulb is still connected across the same battery with the same voltage. So the brightness of the surviving bulb is unchanged, it does not increase or decrease, and it certainly does not switch off.
Hence, the answer is The brightness of the other bulb remains unchanged.
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