Question
Two equal circles pass through each other’s centre. If the radius of each of the circles is 13 cm, then what is the length of the common chord?
This question was previously asked in
SSC CGL 2024 (Tier-I) Previous Year Paper (17-Sep-2024) (Shift 3)
The correct answer is
13√3 cm
The length of the common chord of two equal circles passing through each other's centre can be calculated using the formula derived from geometry, which gives the result 13√3 cm.
Was this answer helpful?
Similar Questions
The value of {15 ÷ 3 × 7 – 8 of 2 + 6} is:
Important Questions from Bodmas Rule
The value of 30 ÷ 6 × 5 of (2 + 3) - 12(3 × 2) is equal to:
solve the following:
523 + 523 × 523 ÷ 523
The value of 96 - 4 of (18 - 13) + 4 × 7 is:
Find the value of 45 - 3 × (4 of 6 + 12 ÷ 3 × 6 - 4 × 5) + 6.
What is the value of
5 ÷ 10 of 10 × 4 + 4 ÷ 4 of 4 × 10 + (10 - 4) ÷ 16 × 4?
Need Expert Advice?
Upcoming Exams
Test Series
SSC
SSC CGL (Tier I + Tier II) 2026 Mock Test Series - Latest Pattern
2500 Tests 6 Tests Free
3728 Attempts
4.2(831)
English, Hindi
More Questions from SSC CGL
