This problem involves calculating the individual monthly salaries of two employees, Anita and Sarita, given their total combined salary and a percentage relationship between their individual salaries.
Let the amount Sarita gets per month be represented by S.
Let the amount Anita gets per month be represented by A.
We are given two pieces of information:
Now, we can substitute the expression for A from the second equation into the first equation:
Substitute $A = 1.2 \times S$ into $A + S = 6600$:
$ (1.2 \times S) + S = 6600 $Combine the terms involving S:
$ 2.2 \times S = 6600 $To find S, divide both sides by 2.2:
$ S = \frac{6600}{2.2} $To simplify the division, multiply the numerator and denominator by 10:
$ S = \frac{66000}{22} $Perform the division:
$ S = 3000 $Therefore, the amount Sarita will get is ₹3,000.
If Sarita gets ₹3,000, then Anita gets:
$ A = 1.2 \times 3000 = 3600 $Their total salary is:
$ A + S = 3600 + 3000 = 6600 $This matches the given total sum.
Radha saves 25% of her income. If her expenditure increases by 20% and her income increases by 29%, then her savings increase by;
The income of A is 45% more than the income of B and the income of C is 60% less than the sum of the incomes of A and B. The income of D is 20% more than that of C. If the difference between the incomes of B and D is Rs. 13200, then the income (in Rs.) of C is:
The price of cooking oil increased by 25%. Find by how much percentage a family must reduce its consumption in order to maintain the same budget.
The population of a city increased by 30% in the first year and decreased by 15% in the next year. If the present population is 11,050 then population 2 years ago was:
The income of A is 30% less than the income of B and the income of B is 137.5% more than that of C. If the income of A is Rs. 28500 less than that of B, then the income (in Rs.) of C is: