The income of A is 30% less than the income of B and the income of B is 137.5% more than that of C. If the income of A is Rs. 28500 less than that of B, then the income (in Rs.) of C is:
40000
This problem involves calculating the income of three individuals, A, B, and C, based on given percentage relationships and a specific difference in income between two of them. We need to use the provided information to find the income of C.
Let's break down the given information about the incomes of A, B, and C:
We can represent these relationships using mathematical equations. Let the incomes of A, B, and C be \(I_A\), \(I_B\), and \(I_C\) respectively.
We know that \(I_B - I_A = 28500\) and \(I_A = 0.70 \times I_B\). We can substitute the expression for \(I_A\) into the difference equation:
\[I_B - (0.70 \times I_B) = 28500\] \[(1 - 0.70) \times I_B = 28500\] \[0.30 \times I_B = 28500\]Now, we can solve for \(I_B\):
\[I_B = \frac{28500}{0.30}\] \[I_B = \frac{285000}{3}\] \[I_B = 95000\]So, the income of B is Rs. 95000.
We have the relationship \(I_B = 2.375 \times I_C\) and we now know \(I_B = 95000\). We can substitute the value of \(I_B\) into this equation:
\[95000 = 2.375 \times I_C\]To find \(I_C\), we need to divide 95000 by 2.375:
\[I_C = \frac{95000}{2.375}\]Let's convert 2.375 to a fraction to make the division easier. \(2.375 = 2 + 0.375\) \(0.375 = \frac{375}{1000} = \frac{3 \times 125}{8 \times 125} = \frac{3}{8}\) So, \(2.375 = 2 + \frac{3}{8} = \frac{16+3}{8} = \frac{19}{8}\).
Now substitute the fraction into the equation for \(I_C\):
\[I_C = \frac{95000}{\frac{19}{8}}\] \[I_C = 95000 \times \frac{8}{19}\] \[I_C = \frac{95000}{19} \times 8\]Since \(95 \div 19 = 5\), it follows that \(95000 \div 19 = 5000\).
\[I_C = 5000 \times 8\] \[I_C = 40000\]Therefore, the income of C is Rs. 40000.
Let's check if these income values satisfy all the conditions:
Check the difference between B and A:
\[I_B - I_A = 95000 - 66500 = 28500\]This matches the given condition that the income of A is Rs. 28500 less than B. The calculated income for C is Rs. 40000.
| Individual | Income (Rs.) |
|---|---|
| C | 40000 |
| B | 95000 |
| A | 66500 |
Here's a summary of the key values and calculations:
| Relationship | Equation | Calculation | Result |
|---|---|---|---|
| A in terms of B | \(I_A = 0.70 \times I_B\) | Derived from "30% less than B" | \(I_A\) is 70% of \(I_B\) |
| B in terms of C | \(I_B = 2.375 \times I_C\) | Derived from "137.5% more than C" | \(I_B\) is 237.5% of \(I_C\) |
| Difference B & A | \(I_B - I_A = 28500\) | Given information | \(I_B - I_A = 28500\) |
| Solve for \(I_B\) | \(0.30 \times I_B = 28500\) | Substituting \(I_A\) | \(I_B = 95000\) |
| Solve for \(I_C\) | \(I_C = I_B / 2.375\) | Using \(I_B\) and relationship | \(I_C = 40000\) |
Understanding how percentage increase and decrease work is crucial for solving such problems. Let's define these concepts:
These concepts are fundamental in solving problems involving percentages, ratios, and proportional relationships often found in quantitative aptitude sections of exams.
Radha saves 25% of her income. If her expenditure increases by 20% and her income increases by 29%, then her savings increase by;
The income of A is 45% more than the income of B and the income of C is 60% less than the sum of the incomes of A and B. The income of D is 20% more than that of C. If the difference between the incomes of B and D is Rs. 13200, then the income (in Rs.) of C is:
The price of cooking oil increased by 25%. Find by how much percentage a family must reduce its consumption in order to maintain the same budget.
The population of a city increased by 30% in the first year and decreased by 15% in the next year. If the present population is 11,050 then population 2 years ago was:
Ravi scores 72% marks in examinations. If these are 360 marks, the maximum marks are: