Two convex lenses with power 2 diopter are kept in contact with each other. The focal length of the combined lens system is
0.25 m
This question asks us to find the focal length of a system formed by two convex lenses placed in contact. We are given the power of each individual lens.
\(P = \frac{1}{f}\) (where \(f\) is in meters and \(P\) is in diopters).When two or more thin lenses are placed in contact with each other, the total power of the combination is simply the algebraic sum of the individual powers of the lenses.
If we have two lenses with powers \(P_1\) and \(P_2\) in contact, the total power \(P_{total}\) is:
\(P_{total} = P_1 + P_2\)
We are given two convex lenses, each with a power of 2 diopters.
Now, we find the total power of the combined lens system:
\(P_{total} = P_1 + P_2\)
\(P_{total} = +2 \, D + (+2) \, D\)
\(P_{total} = 4 \, D\)
The total power of the combined lens system is 4 diopters.
Next, we need to find the focal length of this combined system. We use the relationship between power and focal length:
\(f_{total} = \frac{1}{P_{total}}\)
Substituting the value of \(P_{total}\):
\(f_{total} = \frac{1}{4 \, D}\)
\(f_{total} = 0.25 \, m\)
The focal length of the combined lens system is 0.25 meters.
| Parameter | Value | Unit |
|---|---|---|
| Power of Lens 1 (\(P_1\)) | 2 | Diopters (D) |
| Power of Lens 2 (\(P_2\)) | 2 | Diopters (D) |
| Total Power (\(P_{total} = P_1 + P_2\)) | \(2 + 2 = 4\) |
Diopters (D) |
| Combined Focal Length (\(f_{total} = 1/P_{total}\)) | \(1/4 = 0.25\) |
Meters (m) |
Based on our calculation, the focal length of the combined lens system is 0.25 m. We compare this value with the given options.
Our calculated value matches Option 4.
| Concept | Formula/Rule | Notes |
|---|---|---|
| Lens Power | \(P = 1/f\) (f in meters) |
Unit is Diopter (D). Convex lens: P > 0, f > 0. Concave lens: P < 0, f < 0. |
| Lenses in Contact | \(P_{total} = P_1 + P_2 + \dots\) |
Powers add up algebraically. |
| Combined Focal Length | \(f_{total} = 1/P_{total}\) |
Derived from the total power. |
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