A convex lens of focal length f will form a magnified real image of an object, if the object is placed.
between f and 2f
When dealing with optics, specifically convex lenses, the position of an object relative to the lens determines the characteristics of the image formed. A convex lens is a converging lens, meaning it converges parallel rays of light at a point called the principal focus, which is located at a distance equal to the focal length ($\mathbf{f}$).
The question asks about forming a magnified real image using a convex lens of focal length $\mathbf{f}$. A real image is one that can be projected onto a screen, and it is typically inverted. A magnified image is larger than the object.
Let's examine how the image characteristics change as we move the object closer to a convex lens from a large distance. The key positions are the optical centre (O), the principal focus ($\mathbf{f}$), and twice the focal length ($\mathbf{2f}$), which is also the centre of curvature for the lens surfaces.
Here's a summary of image formation for different object positions:
We can also represent this information in a table for clarity:
| Object Position | Image Position | Image Characteristics |
|---|---|---|
| At infinity | At $\mathbf{f}$ (opposite side) | Real, Inverted, Highly Diminished |
| Beyond $\mathbf{2f}$ | Between $\mathbf{f}$ and $\mathbf{2f}$ (opposite side) | Real, Inverted, Diminished |
| At $\mathbf{2f}$ | At $\mathbf{2f}$ (opposite side) | Real, Inverted, Same Size |
| Between $\mathbf{f}$ and $\mathbf{2f}$ | Beyond $\mathbf{2f}$ (opposite side) | Real, Inverted, Magnified |
| At $\mathbf{f}$ | At infinity (opposite side) | Real, Inverted, Highly Magnified |
| Between optical centre and $\mathbf{f}$ | On the same side as object | Virtual, Erect, Magnified |
Looking at the summary above, we need an image that is both real and magnified. The cases that produce real images are when the object is at infinity, beyond $\mathbf{2f}$, at $\mathbf{2f}$, between $\mathbf{f}$ and $\mathbf{2f}$, or at $\mathbf{f}$.
Out of these real image cases, the ones that produce a magnified image are when the object is placed:
The case when the object is placed between $\mathbf{f}$ and $\mathbf{2f}$ is the standard scenario that produces a magnified real image at a finite distance (beyond $\mathbf{2f}$). Placing the object exactly at $\mathbf{f}$ produces an image at infinity, which, while highly magnified and real, is often considered a limiting case.
Comparing this with the given options, placing the object between $\mathbf{f}$ and $\mathbf{2f}$ clearly results in a magnified real image.
Placing the object "between f and optical centre" produces a magnified virtual image, not a real one. Placing it "anywhere beyond 2f" produces a diminished or same-sized real image, not a magnified one.
Therefore, to obtain a magnified real image with a convex lens, the object must be placed between the focal length ($\mathbf{f}$) and twice the focal length ($\mathbf{2f}$).
Which one of the following statements is not correct for light rays?
A ray of light travelling in the direction \(\frac{1}{2} (\hat i + \sqrt 3 \hat j)\) is incident on a plane mirror. After reflection it travels along the direction \(\frac{1}{2} (\hat i - \sqrt 3 \hat j)\) The angle of incidence is:
Match list one with list two and select the correct answers using the code given below the lists:
List one (Disease) | List two (Remedy) | ||
A | Hypermetropia | 1 | concave lens |
B | Presbyopia | 2 | bifocal lens |
C | Myopia | 3 | Surgery |
D | Cataract | 4 | Convex lens |
Twinkling of stars is due to atmospheric
If an object is placed at infinity from a concave lens of focal length 15 cm, then the distance of virtual image from the lens will be: