To be successful in a competition, Jämglin needs to score an average of 75 in 4 exams. The scores of the previous three exams are 72, 68 and 64, respectively. To succeed in the competition, how much will he have to score in the fourth test?
96
96 is correct.
For an average of 75 in 4 exams, the total score needed is \(75\times4=300\).
Total of the first three exams: \(72+68+64=204\).
Score needed in the fourth exam: \(300-204=96\).
Similar Questions
The average weight of eleven players of the state level cricket team is 109 kg. On joining the coach, the average weight of the team increases by 1kg. How much is the weight of the coach (in kg)?
The average of 7 numbers is 152. On removing a number, the average remains unchanged. Find the number removed.
Important Questions from Average
- Find the mean marks of the following distribution.
Marks obtained No. of students 25 5 30 6 35 3 40 1 - The average of first 169 even numbers is
- The average weight (in kg) of a family of five members whose weights are 40 kg, 49 kg, 56 kg, 74 kg and 35 kg is:
- The average of first 152 odd natural numbers, is:
The average runs scored by a batsman in 23 matches is 40. In the next 10 matches, the batsman scored an average of 16 runs. Find his average runs scored (rounded off to two decimals) in all the 33 matches.
