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Question

Find the mean marks of the following distribution.
Marks obtainedNo. of students
255
306
353
401

This question was previously asked in
RRB NTPC 2024 Undergraduate CBT 1 Question Paper (29-Aug-2025) (Shift 1)
The correct answer is
30

Calculating Mean Marks for a Frequency Distribution

The question asks us to find the average (mean) marks obtained by students based on the provided frequency distribution. A frequency distribution shows how often each value (in this case, marks) occurs.

Understanding the Mean Formula

To calculate the mean of a frequency distribution, we use the following formula:

\( \text{Mean} = \frac{\sum (f \cdot x)}{\sum f} \)

Where:

  • \(x\) represents the individual values (Marks obtained).
  • \(f\) represents the frequency of each value (No. of students).
  • \(\sum (f \cdot x)\) is the sum of the products of each mark and its corresponding frequency.
  • \(\sum f\) is the total number of observations (total number of students).

Step-by-Step Calculation

First, let's create a table to organize the data and calculate the product \(f \cdot x\) for each row.

Marks obtained (\(x\)) No. of students (\(f\)) Product (\(f \cdot x\))
25 5 \(25 \times 5 = 125\)
30 6 \(30 \times 6 = 180\)
35 3 \(35 \times 3 = 105\)
40 1 \(40 \times 1 = 40\)

Next, we sum the frequencies (\(\sum f\)) and the products (\(\sum (f \cdot x)\)).

  • Total number of students: \( \sum f = 5 + 6 + 3 + 1 = 15 \)
  • Sum of the products: \( \sum (f \cdot x) = 125 + 180 + 105 + 40 = 450 \)

Finding the Mean Marks

Now, we apply the mean formula using the calculated sums:

\( \text{Mean} = \frac{\sum (f \cdot x)}{\sum f} = \frac{450}{15} \)

\( \text{Mean} = 30 \)

Therefore, the mean marks obtained by the students in this distribution is 30.

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Similar Questions

  1. The Table given below represents the ages of students in a private music school. What is the average age of the students?
    Age BandStudents
    0 - 104
    10 - 205
    20 - 3015
    30 - 404
  2. Find the mean of the following numbers:
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  3. The average age of a family of 5 members is 20 years, with the youngest member being 5 years old. What was the average age (in years) of the family just before the birth of the youngest member?
  4. The average marks obtained by a group of 16 students was 20. One student left the group as a result of which the average of the remaining students rose to 21. But another student joined, as a result of which the average marks of the group dropped a bit and became 20.5. What was the average marks obtained by the student who left and the one who joined?
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Important Questions from Average

  1. The average of first 169 even numbers is
  2. The average weight (in kg) of a family of five members whose weights are 40 kg, 49 kg, 56 kg, 74 kg and 35 kg is:
  3. The average of first 152 odd natural numbers, is:
  4. The average runs scored by a batsman in 23 matches is 40. In the next 10 matches, the batsman scored an average of 16 runs. Find his average runs scored (rounded off to two decimals) in all the 33 matches.

  5. The sum of five numbers is 655. The average of the first two numbers is 80 and the third number is 101. Find the average of the remaining two numbers.
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