Marks obtained No. of students 25 5 30 6 35 3 40 1
The question asks us to find the average (mean) marks obtained by students based on the provided frequency distribution. A frequency distribution shows how often each value (in this case, marks) occurs.
To calculate the mean of a frequency distribution, we use the following formula:
\( \text{Mean} = \frac{\sum (f \cdot x)}{\sum f} \)
Where:
First, let's create a table to organize the data and calculate the product \(f \cdot x\) for each row.
| Marks obtained (\(x\)) | No. of students (\(f\)) | Product (\(f \cdot x\)) |
|---|---|---|
| 25 | 5 | \(25 \times 5 = 125\) |
| 30 | 6 | \(30 \times 6 = 180\) |
| 35 | 3 | \(35 \times 3 = 105\) |
| 40 | 1 | \(40 \times 1 = 40\) |
Next, we sum the frequencies (\(\sum f\)) and the products (\(\sum (f \cdot x)\)).
Now, we apply the mean formula using the calculated sums:
\( \text{Mean} = \frac{\sum (f \cdot x)}{\sum f} = \frac{450}{15} \)
\( \text{Mean} = 30 \)
Therefore, the mean marks obtained by the students in this distribution is 30.
| Age Band | Students |
|---|---|
| 0 - 10 | 4 |
| 10 - 20 | 5 |
| 20 - 30 | 15 |
| 30 - 40 | 4 |
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