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Question

Find the mean marks of the following distribution.
Marks obtainedNo. of students
255
306
353
401

This question was previously asked in
RRB NTPC 2024 Undergraduate CBT 1 Question Paper (29-Aug-2025) (Shift 1)
The correct answer is
30

Calculating Mean Marks for a Frequency Distribution

The question asks us to find the average (mean) marks obtained by students based on the provided frequency distribution. A frequency distribution shows how often each value (in this case, marks) occurs.

Understanding the Mean Formula

To calculate the mean of a frequency distribution, we use the following formula:

\( \text{Mean} = \frac{\sum (f \cdot x)}{\sum f} \)

Where:

  • \(x\) represents the individual values (Marks obtained).
  • \(f\) represents the frequency of each value (No. of students).
  • \(\sum (f \cdot x)\) is the sum of the products of each mark and its corresponding frequency.
  • \(\sum f\) is the total number of observations (total number of students).

Step-by-Step Calculation

First, let's create a table to organize the data and calculate the product \(f \cdot x\) for each row.

Marks obtained (\(x\)) No. of students (\(f\)) Product (\(f \cdot x\))
25 5 \(25 \times 5 = 125\)
30 6 \(30 \times 6 = 180\)
35 3 \(35 \times 3 = 105\)
40 1 \(40 \times 1 = 40\)

Next, we sum the frequencies (\(\sum f\)) and the products (\(\sum (f \cdot x)\)).

  • Total number of students: \( \sum f = 5 + 6 + 3 + 1 = 15 \)
  • Sum of the products: \( \sum (f \cdot x) = 125 + 180 + 105 + 40 = 450 \)

Finding the Mean Marks

Now, we apply the mean formula using the calculated sums:

\( \text{Mean} = \frac{\sum (f \cdot x)}{\sum f} = \frac{450}{15} \)

\( \text{Mean} = 30 \)

Therefore, the mean marks obtained by the students in this distribution is 30.

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