The median of the observations 4, 14, 11, 8, 7, 8, 9, 12, 4, and 6 is:
8
To find the median of a set of observations, we first need to arrange the data in ascending order.
The given observations are: 4, 14, 11, 8, 7, 8, 9, 12, 4, 6.
Arranging these numbers from the smallest to the largest, we get:
There are 10 observations in total (let's denote this by n, so \(n=10\)). Since n is an even number, the median is the average of the two middle values. The positions of these middle values are calculated as:
Looking at our ordered list:
4, 4, 6, 7, 8, 8, 9, 11, 12, 14
The 5th value is 8, and the 6th value is also 8.
To find the median, we take the average of these two middle values:
Median = \( \frac{\text{5th value} + \text{6th value}}{2} \)
Median = \( \frac{8 + 8}{2} \)
Median = \( \frac{16}{2} \)
Median = 8
Therefore, the median of the given observations is 8.
| Marks obtained | No. of students |
| 25 | 5 |
| 30 | 6 |
| 35 | 3 |
| 40 | 1 |
| Age Band | Students |
|---|---|
| 0 - 10 | 4 |
| 10 - 20 | 5 |
| 20 - 30 | 15 |
| 30 - 40 | 4 |
The weights (in kg) of 9 members of a school cricket team are 50, 63, x, 62, 64, 48, 51, 55, 48. If the mean weight is 56 kg, then the value of x is:
A group of people consists of men, women, and children. 40% of them are men, 35% are women, and the rest are children, and their average weights are 70 kg, 60 kg, and 30 kg, respectively. The average weight of the group is:
If the mean of 22, 25, 27, 24, and x is 26, then the value of x is:
The average of 70 values is 40. If each value is multiplied by 20, what will be the changed average?
| Marks obtained | No. of students |
| 25 | 5 |
| 30 | 6 |
| 35 | 3 |
| 40 | 1 |
The average runs scored by a batsman in 23 matches is 40. In the next 10 matches, the batsman scored an average of 16 runs. Find his average runs scored (rounded off to two decimals) in all the 33 matches.