Here's how to solve this problem step-by-step:
1. Calculate the total score of the first group of students:
The average score of the first 12 students is 68. Therefore, their total score is \(12 \times 68 = 816\).
2. Calculate the total score of the remaining students:
There are 30 students in total, and 12 are in the first group, so there are \(30 - 12 = 18\) students in the second group. Their average score is 70, meaning their total score is \(18 \times 70 = 1260\).
3. Calculate the total score of the entire class:
The total score for the entire class is the sum of the scores of both groups: \(816 + 1260 = 2076\).
4. Calculate the average score of the entire class:
To find the average score, divide the total score by the total number of students: \(\frac{2076}{30} = 69.2\).
Therefore, the average score of the class is 69.2.
| Marks obtained | No. of students |
| 25 | 5 |
| 30 | 6 |
| 35 | 3 |
| 40 | 1 |
| Age Band | Students |
|---|---|
| 0 - 10 | 4 |
| 10 - 20 | 5 |
| 20 - 30 | 15 |
| 30 - 40 | 4 |
The median of the observations 4, 14, 11, 8, 7, 8, 9, 12, 4, and 6 is:
The weights (in kg) of 9 members of a school cricket team are 50, 63, x, 62, 64, 48, 51, 55, 48. If the mean weight is 56 kg, then the value of x is:
A group of people consists of men, women, and children. 40% of them are men, 35% are women, and the rest are children, and their average weights are 70 kg, 60 kg, and 30 kg, respectively. The average weight of the group is:
If the mean of 22, 25, 27, 24, and x is 26, then the value of x is:
The average of 70 values is 40. If each value is multiplied by 20, what will be the changed average?
| Marks obtained | No. of students |
| 25 | 5 |
| 30 | 6 |
| 35 | 3 |
| 40 | 1 |
The average runs scored by a batsman in 23 matches is 40. In the next 10 matches, the batsman scored an average of 16 runs. Find his average runs scored (rounded off to two decimals) in all the 33 matches.