Three numbers are in the ratio 3 : 2 : 11, and their LCM is 3564. Their HCF is:
54
Let the numbers be 3k, 2k, 11k. Their LCM: \(k\times\text{LCM}(3,2,11) = k\times66 = 3564 \Rightarrow k=54\).
HCF of the numbers: \(k\times\text{HCF}(3,2,11) = 54\times1 = 54\).
Hence, the HCF of the three numbers is 54.
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Important Questions from LCM and HCF
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A and B are two prime numbers such that A > B and their LCM is 209. The value of A 2 - B is:
Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.
Calculate the HCF of \(\frac{12}{5}\) , \(\frac{14}{15}\) and \(\frac{16}{17}\) .
Three numbers are in the proportion of 3 : 8 : 15 and their LCM is 8280. What is their HCF?
