The problem asks us to identify two numbers based on their sum and Least Common Multiple (L.C.M.).
Let the two numbers be $a$ and $b$. The given conditions are:
We can examine the provided options to find the pair that satisfies both conditions. Let's verify Option 2 (90, 42):
Check if the sum of 90 and 42 equals 132.
$90 + 42 = 132$. The sum condition is satisfied.
Calculate the L.C.M. of 90 and 42.
First, find the prime factorization of each number:
The L.C.M. is found by taking the highest power of each prime factor present in either factorization:
L.C.M.(90, 42) = $2^1 \times 3^2 \times 5^1 \times 7^1 = 2 \times 9 \times 5 \times 7 = 18 \times 35 = 630$.
The L.C.M. condition is also satisfied.
Since the pair (90, 42) meets both the sum requirement ($132$) and the L.C.M. requirement ($630$), this is the correct pair of numbers.
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