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Question

The sum of two numbers is 132 and their L.C.M. is 630. What are the two numbers?

This question was previously asked in
RRB NTPC 2024 CBT 1 Question Paper (28-Aug-2025) (Shift 3)
The correct answer is
90, 42

Sum and LCM Numbers: Finding the Pair

The problem asks us to identify two numbers based on their sum and Least Common Multiple (L.C.M.).

Let the two numbers be $a$ and $b$. The given conditions are:

  • Sum: $a + b = 132$
  • L.C.M.: L.C.M.($a$, $b$) = 630

Options Verification for Sum and LCM

We can examine the provided options to find the pair that satisfies both conditions. Let's verify Option 2 (90, 42):

  • Verify Sum:

    Check if the sum of 90 and 42 equals 132.

    $90 + 42 = 132$. The sum condition is satisfied.

  • Verify L.C.M.:

    Calculate the L.C.M. of 90 and 42.

    First, find the prime factorization of each number:

    • $90 = 2 \times 45 = 2 \times 3 \times 15 = 2 \times 3 \times 3 \times 5 = 2 \times 3^2 \times 5$
    • $42 = 2 \times 21 = 2 \times 3 \times 7$

    The L.C.M. is found by taking the highest power of each prime factor present in either factorization:

    L.C.M.(90, 42) = $2^1 \times 3^2 \times 5^1 \times 7^1 = 2 \times 9 \times 5 \times 7 = 18 \times 35 = 630$.

    The L.C.M. condition is also satisfied.

Since the pair (90, 42) meets both the sum requirement ($132$) and the L.C.M. requirement ($630$), this is the correct pair of numbers.

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  2. The HCF of two numbers is 16 and their LCM is 240. If one number is 48, find the other number.
  3. The LCM of the numbers 12.8 and 0.004 is:
  4. Find the least number which is divisible by first ten natural numbers.
  5. Find the HCF of ($3^{45} - 1$) and ($3^{35} - 1$).
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Important Questions from LCM and HCF

  1. Six bells begin to toll together and toll, respectively, at intervals of 3, 4, 6, 7, 8 and 12 seconds. After how many seconds, will they toll together again?

  2. A and B are two prime numbers such that A > B and their LCM is 209. The value of A 2 - B is:

  3. Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

  4. Calculate the HCF of \(\frac{12}{5}\) \(\frac{14}{15}\)  and  \(\frac{16}{17}\) .

  5. Three numbers are in the proportion of 3 : 8 : 15 and their LCM is 8280. What is their HCF?

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