Three fair coins are tossed simultaneously. What is the probability of getting at least one head ?
7/8
Tossing three fair coins gives \(2^3 = 8\) equally likely outcomes.
The only outcome with no heads at all is all tails (TTT), which has probability \(\frac{1}{8}\).
So the probability of at least one head is \(1 - \frac{1}{8} = \frac{7}{8}\).
The probability of getting at least one head is 7/8.
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