Consider a case where two identical six-faced fair dice are rolled simultaneously. The probability of getting even numbers in both AND a sum equal to 5 and above is ______ (rounded off to two decimal places).
We need to find the probability of rolling two identical fair dice such that both dice show even numbers AND their sum is 5 or greater.
First, identify outcomes where both dice show even numbers. The even numbers are {2, 4, 6}. The possible pairs are:
There are $3 \times 3 = 9$ such outcomes.
Next, from these 9 outcomes, identify those where the sum is 5 or greater ($\text{Sum} \ge 5$):
There are 8 outcomes that satisfy both conditions.
The probability is the ratio of favorable outcomes to the total possible outcomes.
Probability = $\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{8}{36}$
Simplifying the fraction:
Probability = $\frac{8}{36} = \frac{2}{9}$
Converting the fraction to a decimal:
Probability $\approx 0.2222...$
Rounding to two decimal places, the probability is 0.22.
This value (0.22) lies between 0.21 and 0.23.