There were 25 employees in an office. The mean salary of the employees was Rs. 30,000 per month. A senior officer having a salary of Rs. 60,000 per month retired, and a new clerk was appointed in his place. The mean salary of the employees in the office was thus reduced by Rs. 1,000 per month. The salary of the new clerk (per month) was:
Rs. 35,000
This problem involves understanding how the mean (average) salary of a group of employees changes when one employee leaves and another joins. The mean is calculated as the total sum of salaries divided by the number of employees.
The key is to find the total salary of all employees before the change and after the change. The difference in the total salary, after accounting for the retired officer's salary, will reveal the new clerk's salary.
Initially, we have:
The total salary of all employees initially can be calculated using the formula:
\(\text{Total Salary} = \text{Number of Employees} \times \text{Mean Salary}\)
Initial Total Salary = \(25 \times 30,000\)
Initial Total Salary = Rs. 750,000
A senior officer retired with a salary of Rs. 60,000. This means the total salary of the remaining 24 employees is reduced by this amount.
A new clerk is appointed in his place. The number of employees is back to 25.
The new mean salary is reduced by Rs. 1,000. So, the new mean salary is:
New Mean Salary = Initial Mean Salary - Rs. 1,000
New Mean Salary = \(30,000 - 1,000 = 29,000\)
With the new mean salary and the number of employees back to 25, we can calculate the new total salary of all employees:
New Total Salary = \(25 \times 29,000\)
New Total Salary = Rs. 725,000
Let the salary of the new clerk be \(x\).
The initial total salary (Rs. 750,000) was the sum of the salaries of the senior officer (Rs. 60,000) and the salaries of the other 24 employees.
So, Sum of salaries of the other 24 employees = Initial Total Salary - Senior Officer's Salary
Sum of salaries of the other 24 employees = \(750,000 - 60,000 = 690,000\)
The new total salary (Rs. 725,000) is the sum of the salaries of these same 24 employees and the new clerk's salary (\(x\)).
New Total Salary = (Sum of salaries of the other 24 employees) + New Clerk's Salary
\(725,000 = 690,000 + x\)
Now, we can solve for \(x\):
\(x = 725,000 - 690,000\)
\(x = 35,000\)
The salary of the new clerk is Rs. 35,000 per month.
| Initial Number of Employees | 25 |
| Initial Mean Salary | Rs. 30,000 |
| Initial Total Salary | \(25 \times 30,000 = \text{Rs. } 750,000\) |
| Retired Officer's Salary | Rs. 60,000 |
| Number of Employees after appointment | 25 |
| New Mean Salary | \(30,000 - 1,000 = \text{Rs. } 29,000\) |
| New Total Salary | \(25 \times 29,000 = \text{Rs. } 725,000\) |
| Difference in Total Salary | \(750,000 - 725,000 = \text{Rs. } 25,000\) |
| Salary of 24 remaining employees | \(750,000 - 60,000 = \text{Rs. } 690,000\) |
| New Clerk's Salary | \(725,000 - 690,000 = \text{Rs. } 35,000\) |
The salary of the new clerk is Rs. 35,000 per month.
| Concept | Formula/Explanation | Application in Problem |
|---|---|---|
| Mean (Average) | Sum of values / Number of values | Used to calculate initial and final total salaries. |
| Total Sum from Mean | Mean \(\times\) Number of items | Initial Total Salary = \(30000 \times 25\), New Total Salary = \(29000 \times 25\). |
| Change in Total Sum | New Total Sum - Old Total Sum | The difference in total salary reflects the change due to the swap of employees. |
| Finding Unknown Value | Set up an equation based on total sum before and after the change. | Old Total - Retired Salary + New Salary = New Total. |
This problem illustrates how a single value (an individual's salary) affects the overall mean of a dataset (the average office salary). When a high value (the senior officer's salary) is replaced by a lower value (the new clerk's salary), the total sum decreases, and consequently, the mean decreases, assuming the number of items remains the same.
If the new employee's salary were higher than the retiring employee's, the mean would increase. If the new salary were exactly the same, the mean would remain unchanged.
The change in the mean is directly related to the difference between the value leaving the group and the value entering the group, divided by the number of items in the group.
Change in Mean = (Value Added - Value Removed) / Number of Items
In this case: \(-1000 = (x - 60000) / 25\)
\(-1000 \times 25 = x - 60000\)
\(-25000 = x - 60000\)
\(x = 60000 - 25000\)
\(x = 35000\)
This confirms the result obtained through the total sum method.
The average of 25 numbers is 36. If the average of first 13 numbers is 32 and that of the last 13 numbers is 39, then the 13th number is
The mode (correct to two decimal places) for the given data is:
Class- interval | Frequency |
0-10 | 6 |
10-20 | 9 |
20-30 | 8 |
30-40 | 14 |
40-50 | 28 |
50-60 | 20 |
60-70 | 11 |
70-80 | 9 |
The arithmetic mean of marks of the students for the given data is:
Marks | No. of students |
0-10 | 12 |
10-20 | 18 |
20-30 | 27 |
30-40 | 20 |
40-50 | 17 |
50-60 | 60 |
The incomes of the employees in a state is assumed to be normally distributed with mean Rs.15,000 and variance Rs. 900. The median of the distribution of the income is:
For a moderately skewed distribution, let mode = 15, median = 17.4. The value of mean is:
For the data set with the following observations, the first and second quartiles are:
20, 22, 23, 22, 23, 22, 22, 21, 19, 22, 22, 26, 23, 24, 19, 21, 22, 16
For an asymmetric distribution, if the mean and median are 20 and 30, then the value of the mode is:
For a data set with 24 observations given below, the median is:
10, 11, 13, 13, 18, 20, 22, 22, 24, 24, 25, 29, 30, 31, 35, 37, 37, 37, 46, 51, 54, 55, 61, 64
There are 35 students in a hostel. If the number of students increases by 7, the expenses of the hostel increases by Rs. 42 per day while the average
expenditure per head diminishes by Re. 1. The original expenditure of the hostel is:
If \(P=\dfrac{\sum^n_{i=1}(x_i-A)^2}{\sum^n_{i=1}(x_i-\bar x)^2};A\ne\bar x,\) (x̅ = Arithmetic Mean) then P is:
A random sample of 20 people is classified in the following table according to their ages:
Age | Frequency |
15 – 25 | 2 |
25 – 35 | 4 |
35 – 45 | 6 |
45 – 55 | 5 |
55 - 65 | 3 |
What is the mean age of this group of people?
If the difference of mode and median is 36, then the difference of median and mean is:
In a Mathematics test 15 students scored 80 marks, 20 students scored 75 marks, 28 students scored 65 marks and 25 students scored 60 marks, mode of the score is:
If the mode of the scores 10, 12, 13, 15, 15, 13, 12, 10, x is 15, then what is the value of x?
The average of 25 numbers is 36. If the average of first 13 numbers is 32 and that of the last 13 numbers is 39, then the 13th number is