There are 17 cricket players, out of which 5 players can bowl. In how many ways can a team of 11 players be selected so to include 3 bowlers?
C (5, 3) × C (12, 8)
This question asks about the number of ways to select a cricket team with specific conditions. We have a total pool of 17 players, and we need to form a team of 11 players. A key constraint is that the team must include exactly 3 bowlers from the 5 available bowlers.
The problem is a classic example of combination, where the order of selecting players does not matter. We need to select players for two distinct roles: bowlers and non-bowlers (other players). The total number of players in the pool is 17. Out of these, 5 are bowlers, and the remaining players are non-bowlers. The number of non-bowlers is calculated as:
Total players - Number of bowlers = Non-bowlers
$17 - 5 = 12$ non-bowlers.
We need to select a team of 11 players. The condition is that exactly 3 of these 11 players must be bowlers.
To select a team of 11 players with exactly 3 bowlers, we can break the selection process into two independent steps:
We need to select exactly 3 bowlers for the team. There are 5 bowlers available in the total pool of 17 players. The number of ways to select 3 bowlers from 5 available bowlers is given by the combination formula $\binom{n}{k} = \frac{n!}{k!(n-k)!}$, where $n$ is the total number of items to choose from, and $k$ is the number of items to choose.
Here, $n=5$ (total bowlers) and $k=3$ (bowlers to select).
Number of ways to select 3 bowlers from 5 = $\binom{5}{3}$ ways.
The total team size is 11 players. We have already selected 3 bowlers in Step 1. The remaining players for the team must be non-bowlers. The number of non-bowlers needed for the team is:
Total team size - Number of bowlers selected = Number of non-bowlers needed
$11 - 3 = 8$ non-bowlers.
These 8 non-bowlers must be selected from the pool of non-bowlers. We calculated earlier that there are 12 non-bowlers available (17 total players - 5 bowlers).
The number of ways to select 8 non-bowlers from 12 available non-bowlers is given by the combination formula:
Here, $n=12$ (total non-bowlers) and $k=8$ (non-bowlers to select).
Number of ways to select 8 non-bowlers from 12 = $\binom{12}{8}$ ways.
Since the selection of bowlers and the selection of non-bowlers are independent events, the total number of ways to form the team of 11 players with exactly 3 bowlers is the product of the number of ways for each step. This is based on the multiplication principle of counting.
Total number of ways = (Ways to select 3 bowlers) $\times$ (Ways to select 8 non-bowlers)
Total number of ways = $\binom{5}{3} \times \binom{12}{8}$.
This can also be written in the notation C(n, k):
Total number of ways = C(5, 3) $\times$ C(12, 8).
Let's briefly look at the values:
Total ways = $10 \times 495 = 4950$.
The number of ways is the product of C(5, 3) and C(12, 8).
Let's compare our derived result with the given options:
| Term | Description | Formula |
|---|---|---|
| Combination | Selecting items from a group where the order does not matter. | $\binom{n}{k} = C(n, k) = \frac{n!}{k!(n-k)!}$ |
| n | Total number of items available. | - |
| k | Number of items to be selected. | - |
| Multiplication Principle | If an event can occur in $m$ ways and another independent event can occur in $n$ ways, then both events can occur in $m \times n$ ways. | $m \times n$ |
Team selection problems often involve various conditions. Here are a few common variations related to selecting players:
Understanding the composition of the total pool (bowlers vs. non-bowlers in this case) and the requirements for the final team composition is crucial for solving these combination problems correctly using the appropriate formulas and principles like the multiplication principle.
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