The value of k, for which the system of equations 3x – ky – 20 = 0 and 6x – 10y + 40 = 0 has no solution, is
5
Concept:
For no solution, a 1 /a 2 = b 1 /b 2 ≠ c 1 /c 2
Calculation:
For 3x – ky – 20 = 0, a 1 = 3, b 1 = -k and c1 = -20
For 6x – 10y + 40 = 0, a 2 = 6, b 2 = -10 and c1 = 40
⇒ a1/a2 = b1/b2
⇒ 3/6 = -k/ (-10)
⇒ k = 5
Let's check if b1/b2 ≠ c1/c2
⇒ 5/ (-10) (= 2) ≠ -20/40 (= -2)
∴ There is no solution for k = 5
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