The value of \(\frac{{\rm cose{c^2}30^\circ {{\rm \sin }^2}45^\circ + {{\rm \sec }^2}60^\circ }}{{\rm tan60^\circ \rm cose{c^2}45^\circ - {{\rm \sec }^2}60^\circ \rm tan45^\circ }}\) is:
3/(√3 - 2)
This solution explains how to find the value of the given trigonometric expression involving specific angles.
To solve this problem, we first need to recall the values of the trigonometric functions for the angles 30°, 45°, and 60°.
| Trigonometric Function | Angle (\(^\circ\)) | Value | Squared Value (\( ^2 \)) |
|---|---|---|---|
| \(\rm cosec\) | 30 | 2 | 4 |
| \(\rm \sin\) | 45 | \(\frac{1}{\sqrt{2}}\) | \(\frac{1}{2}\) |
| \(\rm \sec\) | 60 | 2 | 4 |
| \(\rm tan\) | 60 | \(\sqrt{3}\) | 3 |
| \(\rm cosec\) | 45 | \(\sqrt{2}\) | 2 |
| \(\rm tan\) | 45 | 1 | 1 |
The expression given is:
\(\frac{{\rm cose{c^2}30^\circ {{\rm \sin }^2}45^\circ + {{\rm \sec }^2}60^\circ }}{{\rm tan60^\circ \rm cose{c^2}45^\circ - {{\rm \sec }^2}60^\circ \rm tan45^\circ }}\)
Let's calculate the value of the numerator first:
\(\rm cose{c^2}30^\circ {{\rm \sin }^2}45^\circ + {{\rm \sec }^2}60^\circ\)
Substitute the known values:
\( = (2)^2 \times \left(\frac{1}{\sqrt{2}}\right)^2 + (2)^2 \)
Simplify the squares:
\( = 4 \times \frac{1}{2} + 4 \)
Perform the multiplication:
\( = 2 + 4 \)
Result of the numerator:
\( = 6 \)
Now, let's calculate the value of the denominator:
\(\rm tan60^\circ \rm cose{c^2}45^\circ - {{\rm \sec }^2}60^\circ \rm tan45^\circ\)
Substitute the known values:
\( = (\sqrt{3}) \times (\sqrt{2})^2 - (2)^2 \times (1) \)
Simplify the squares and multiplication:
\( = \sqrt{3} \times 2 - 4 \times 1 \)
\( = 2\sqrt{3} - 4 \)
Now, divide the calculated numerator by the calculated denominator:
\(\text{Expression Value} = \frac{\text{Numerator}}{\text{Denominator}} = \frac{6}{2\sqrt{3} - 4}\)
We can simplify this fraction by factoring out a 2 from the denominator:
\( = \frac{6}{2(\sqrt{3} - 2)} \)
Cancel out the common factor of 2:
\( = \frac{3}{\sqrt{3} - 2} \)
The calculated value of the expression is \(\frac{3}{\sqrt{3} - 2}\).
Comparing this result with the given options:
Our calculated value \(\frac{3}{\sqrt{3} - 2}\) directly matches Option 2.
If \(\rm \frac{{(1 - \cos \theta )}}{{\sin \theta }}\) = \(\frac{1}{5}\) , then what will be the value of \(\rm \frac{{(1 + \cos \theta )}}{{\sin \theta }}\) ?
If \(sec\theta = \frac{a}{b},b \ne 0,then\frac{{1 - {{\tan }^2}\theta }}{{2 - {{\sin }^2}\theta }}\) =?
In ΔPQR, ∠Q = 90°. If cot R= \(\frac{1}{3},\) then what is the value of \(\frac{secP(cosR+sinP)}{cosecR(sinR-cosec P)}\) ?
The value of \(\frac{{{{\cos }^4}\theta + {{\sin }^4}\theta + 2{{\sin }^2}\theta {{\cos }^2}\theta }}{{cosec\theta \sec\theta \left( {\sin\theta + \cos\theta - 1} \right)\left( {\sin\theta + \cos\theta + 1} \right)}}\) is:
If x = sec 57°, then cot 233° + sin 257° + sin 233° + cosec 257° cos 233° + sec 233° sin 257° is equal to
The value of (tan 2 A + cot 2 A - 2) - sec 2 A cosec 2 A is:
The value of \(\frac{sin \theta + cos \theta - 1}{sin \theta - cos \theta + 1} \times \sqrt{\frac{1 + sin \theta}{1 - sin \theta}}\) is:
If cosec 39° = x, then the value of \(\frac 1 {\rm cosec^2\;51^\circ} + \sin^2 39^\circ + \tan^2 51^\circ - \frac 1 {\sin^2 51^\circ\sec^2 39^\circ}\) is:
If \(\cos θ = \frac 5 {13},\) then the value of tan 2 θ + sec 2 θ is equal to:
(secθ + tanθ)/(secθ - tanθ) is equal to:
If tan 45°, cot θ then the value of θ, in radians is
ABC is a triangle If sin (A+B)/2 = √3/2, then the value of sin C/2 is
The angles of elevation of the top of a temple, from the foot and the top of a building 30 m high, are 60° and 30° respectively. Then height of the temple is
The value of sin θ and cos θ when the angle θ is 0 ≤ θ ≤ 90°, is ______