\(\frac{sin^2 \ \theta}{cos\theta(1 + cos\theta)} +\frac{1 + cos \theta}{cos\theta} = \ ?\)
2secθ
We are asked to simplify the given trigonometric expression:
$$ \frac{\sin^2 \theta}{\cos\theta(1 + \cos\theta)} + \frac{1 + \cos \theta}{\cos\theta} $$
To simplify this expression, we need to combine the two fractions. First, find a common denominator, which is \( \cos\theta(1 + \cos\theta) \).
The first fraction already has the common denominator. For the second fraction, \( \frac{1 + \cos \theta}{\cos\theta} \), we need to multiply the numerator and the denominator by \( (1 + \cos\theta) \).
So the expression becomes:
$$ \frac{\sin^2 \theta}{\cos\theta(1 + \cos\theta)} + \frac{(1 + \cos \theta) \times (1 + \cos \theta)}{\cos\theta \times (1 + \cos \theta)} $$
This simplifies to:
$$ \frac{\sin^2 \theta}{\cos\theta(1 + \cos\theta)} + \frac{(1 + \cos \theta)^2}{\cos\theta(1 + \cos\theta)} $$
Now that both fractions have the same denominator, we can combine their numerators:
$$ \frac{\sin^2 \theta + (1 + \cos \theta)^2}{\cos\theta(1 + \cos\theta)} $$
Expand the term \( (1 + \cos \theta)^2 \) in the numerator:
$$ (1 + \cos \theta)^2 = 1^2 + 2(1)(\cos \theta) + (\cos \theta)^2 = 1 + 2\cos \theta + \cos^2 \theta $$
Substitute this back into the numerator:
$$ \frac{\sin^2 \theta + 1 + 2\cos \theta + \cos^2 \theta}{\cos\theta(1 + \cos\theta)} $$
Rearrange the terms in the numerator to group \( \sin^2 \theta \) and \( \cos^2 \theta \):
$$ \frac{(\sin^2 \theta + \cos^2 \theta) + 1 + 2\cos \theta}{\cos\theta(1 + \cos\theta)} $$
Using the fundamental trigonometric identity \( \sin^2 \theta + \cos^2 \theta = 1 \), substitute 1 for \( (\sin^2 \theta + \cos^2 \theta) \):
$$ \frac{1 + 1 + 2\cos \theta}{\cos\theta(1 + \cos\theta)} $$
Simplify the numerator:
$$ \frac{2 + 2\cos \theta}{\cos\theta(1 + \cos\theta)} $$
Factor out 2 from the numerator:
$$ \frac{2(1 + \cos \theta)}{\cos\theta(1 + \cos\theta)} $$
Assuming \( 1 + \cos \theta \neq 0 \), we can cancel the term \( (1 + \cos \theta) \) from the numerator and the denominator:
$$ \frac{2}{\cos\theta} $$
Using the reciprocal identity \( \sec \theta = \frac{1}{\cos \theta} \), we can rewrite the expression as:
$$ 2 \times \frac{1}{\cos\theta} = 2\sec \theta $$
Thus, the simplified expression is \( 2\sec \theta \).
| Identity | Formula |
|---|---|
| Pythagorean Identity | \( \sin^2 \theta + \cos^2 \theta = 1 \) |
| Reciprocal Identity | \( \sec \theta = \frac{1}{\cos \theta} \) |
Trigonometric functions relate the angles of a right triangle to the ratios of its sides. The basic trigonometric functions are sine, cosine, and tangent. Their reciprocals are cosecant, secant, and cotangent.
Simplifying trigonometric expressions often involves using these definitions and fundamental identities like the Pythagorean identities to rewrite the expression in a simpler form.
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