Which of the following is a FALSE statement?
tan2 A = 1 - sec2 A
The question asks us to identify the statement that is FALSE among the given trigonometric identities. To do this, we will examine each statement and check if it holds true based on fundamental trigonometric identities.
We will use the following well-known trigonometric identities:
Let's check each given statement one by one:
We know the Pythagorean identity $1 + \tan^2 A = \sec^2 A$. Let's rearrange this identity to express $\tan^2 A$:
From $1 + \tan^2 A = \sec^2 A$, we subtract 1 from both sides:
$\tan^2 A = \sec^2 A - 1$
Now let's look at the given statement: $\tan^2 A = 1 - \sec^2 A$. We can rewrite $1 - \sec^2 A$ as $-(\sec^2 A - 1)$.
So the statement is $\tan^2 A = -(\sec^2 A - 1)$.
Comparing this with the correct identity $\tan^2 A = \sec^2 A - 1$, we see that the given statement claims $\tan^2 A = - \tan^2 A$. This is only true if $\tan^2 A = 0$, which means $\tan A = 0$. This identity does not hold true for all values of A where $\tan A$ and $\sec A$ are defined. Therefore, this statement is FALSE.
We know the ratio identity $\tan A = \frac{\sin A}{\cos A}$ (assuming $\cos A \neq 0$). Let's substitute this into the right side of the statement:
Right Side = $\tan A \times \cos A = \left(\frac{\sin A}{\cos A}\right) \times \cos A$
Assuming $\cos A \neq 0$, we can cancel $\cos A$:
Right Side = $\sin A$
The statement becomes $\sin A = \sin A$, which is TRUE for all values of A where $\tan A$ and $\cos A$ are defined and $\cos A \neq 0$.
We know the Pythagorean identity $1 + \cot^2 A = \cosec^2 A$. Let's rearrange this identity to isolate $\cot^2 A$:
From $1 + \cot^2 A = \cosec^2 A$, we subtract 1 from both sides:
$\cot^2 A = \cosec^2 A - 1$
This matches the given statement exactly. Therefore, this statement is TRUE for all values of A where $\cot A$ and $\cosec A$ are defined.
We know the reciprocal identity $\sec A = \frac{1}{\cos A}$ (assuming $\cos A \neq 0$). Let's substitute this into the left side of the statement:
Left Side = $\cos A \times \sec A = \cos A \times \left(\frac{1}{\cos A}\right)$
Assuming $\cos A \neq 0$, we can cancel $\cos A$:
Left Side = 1
The statement becomes $1 = 1$, which is TRUE for all values of A where $\cos A$ and $\sec A$ are defined and $\cos A \neq 0$.
Based on our analysis of each trigonometric statement, we found that statement 1 is the only one that is FALSE. The correct identity relating $\tan^2 A$ and $\sec^2 A$ is $\tan^2 A = \sec^2 A - 1$, not $\tan^2 A = 1 - \sec^2 A$.
| Statement | Analysis | Truth Value |
|---|---|---|
| $\tan^2 A = 1 - \sec^2 A$ | Derived from $1 + \tan^2 A = \sec^2 A$ gives $\tan^2 A = \sec^2 A - 1$. The given statement is $\tan^2 A = -(\sec^2 A - 1) = -\tan^2 A$, which is not generally true. | FALSE |
| $\sin A = \tan A \times \cos A$ | Substitute $\tan A = \frac{\sin A}{\cos A}$. RHS = $\frac{\sin A}{\cos A} \times \cos A = \sin A$ (for $\cos A \neq 0$). LHS = RHS. | TRUE |
| $\cosec^2 A - 1 = \cot^2 A$ | Rearranging $1 + \cot^2 A = \cosec^2 A$ gives $\cot^2 A = \cosec^2 A - 1$. Matches the statement. | TRUE |
| $\cos A \times \sec A = 1$ | Substitute $\sec A = \frac{1}{\cos A}$. LHS = $\cos A \times \frac{1}{\cos A} = 1$ (for $\cos A \neq 0$). LHS = RHS. | TRUE |
| Type of Identity | Identity | Notes |
|---|---|---|
| Pythagorean | $\sin^2 A + \cos^2 A = 1$ | Foundation identity |
| Derived Pythagorean | $1 + \tan^2 A = \sec^2 A$ | Derived by dividing $\sin^2 A + \cos^2 A = 1$ by $\cos^2 A$ |
| Derived Pythagorean | $1 + \cot^2 A = \cosec^2 A$ | Derived by dividing $\sin^2 A + \cos^2 A = 1$ by $\sin^2 A$ |
| Reciprocal | $\sec A = \frac{1}{\cos A}$ | Valid when $\cos A \neq 0$ |
| Reciprocal | $\cosec A = \frac{1}{\sin A}$ | Valid when $\sin A \neq 0$ |
| Reciprocal | $\cot A = \frac{1}{\tan A}$ | Valid when $\tan A \neq 0$ |
| Ratio | $\tan A = \frac{\sin A}{\cos A}$ | Valid when $\cos A \neq 0$ |
| Ratio | $\cot A = \frac{\cos A}{\sin A}$ | Valid when $\sin A \neq 0$ |
Trigonometric identities are equations that are true for all values of the variable for which the expressions are defined. They are crucial in simplifying trigonometric expressions, solving trigonometric equations, and calculating derivatives and integrals of trigonometric functions.
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