The value of \((\cos^2 67° - \sin^2 23°) + 4\cos 30°\) is:
\(2\sqrt{3}\)
Use the complementary-angle identity \(\sin\theta = \cos(90° - \theta)\).
Since \(\sin 23° = \cos(90° - 23°) = \cos 67°\), we get \(\sin^2 23° = \cos^2 67°\).
Therefore \(\cos^2 67° - \sin^2 23° = 0\).
The expression becomes \(0 + 4\cos 30° = 4 \times \frac{\sqrt{3}}{2} = 2\sqrt{3}\).
Hence, the value of the expression is \(2\sqrt{3}\).
The value of 5 sin 14° sec 76° + 3 cot 15° cot 75° + 2 tan 45° is:
If two complimentary angles are in the ratio of 4 : 5, find the greater angle.
If \(\frac{\sin\spaceθ \space+\space \cos\spaceθ} {\sin \spaceθ \space-\space \cos \spaceθ} = \frac{\sqrt3 \space-\space 1}{\sqrt3 \space+\space 1} \) , then the angle θ is
If tan α = 1/2, tan β = 1/3, then find α + β.
Simplify: sin (A + B) sin (A – B)