The value of \(3(\sec^{2}\theta + \operatorname{cosec}^{2}\theta) - 10(\cot^{2}\theta \times \cos^{2}\theta)\), when θ = 45°, is:
7
At theta = 45 degrees, sec²theta = cosec²theta = 2, cot²theta = 1 and cos²theta = 0.5. So 3(2+2) - 10(1 x 0.5) = 12 - 5 = 7. Hence, the correct answer is 7.
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