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Question

The total number of metal-metal bonds in $Ru_3(CO)_{12}$ and $Co_4(CO)_{12}$, respectively, is

The correct answer is
3 and 6

Ru3(CO)12 Bond Count

The structure of $\text{Ru}_3(\text{CO})_{12}$ consists of a triangle formed by three Ruthenium (Ru) metal atoms. Each side of this triangle represents a direct Ru-Ru metal-metal bond.

  • Number of Ru-Ru bonds = 3

Co4(CO)12 Bond Count

The structure of $\text{Co}_4(\text{CO})_{12}$ is based on a tetrahedron formed by four Cobalt (Co) metal atoms. A tetrahedron has 6 edges, and each edge corresponds to a direct Co-Co metal-metal bond.

  • Number of Co-Co bonds = 6

Total Metal-Metal Bonds

The total number of metal-metal bonds in $\text{Ru}_3(\text{CO})_{12}$ is 3, and in $\text{Co}_4(\text{CO})_{12}$ is 6.

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Important Questions from Organometallic Chemistry

  1. The species that undergoes $\beta$-elimination is
  2. The heptacity of allyl and Cp and the ligation mode of NO in the thermodynamically stable complexes 
    $[(\eta^x-allyl)Ru(CO)_2(NO)]$ and $[(\eta^y-Cp)Ru(CO)_2(NO)]$, 
    respectively, are 
    (The heptacity of allyl and Cp are denoted by $\eta^x$ and $\eta^y$, respectively.)

  3. The bond angle (Ti-C-C) in the crystal structure of

    is severely distorted due to

  4. The major product of the following reaction sequence is

  5. Decarbonylation reaction of $[cis-(CH_3CO)Mn(^{13}CO)(CO)_4]$ yields X,Y and Z, where $X =[(CH_3)Mn(CO)_5]$; $Y = [cis-(CH_3)Mn(^{13}CO)(CO)_4]$; $Z = [trans-(CH_3)Mn(^{13}CO)(CO)_4]$ 

    The molar ratio of the products(X : Y : Z) in this reaction is

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