The sum of three fractions A, B, and C, A > B > C, is \(\frac{121}{60}\) . When C is divided by B, the resulting fraction is \(\frac{9}{10}\) , which exceeds A by \(\frac{3}{20}\) . What is the difference between B and C?
This problem involves finding the values of three fractions, A, B, and C, based on given relationships, and then calculating the difference between two of them. We are given three key pieces of information:
Our goal is to find the difference between B and C, which is \(B - C\).
We are given that the result of C divided by B, which is \(\frac{9}{10}\), exceeds A by \(\frac{3}{20}\). This can be written as an equation:
\(\frac{9}{10} = A + \frac{3}{20}\)
To find A, we need to subtract \(\frac{3}{20}\) from \(\frac{9}{10}\):
\(A = \frac{9}{10} - \frac{3}{20}\)
To subtract these fractions, we find a common denominator, which is 20. We convert \(\frac{9}{10}\) to an equivalent fraction with a denominator of 20:
\(\frac{9}{10} = \frac{9 \times 2}{10 \times 2} = \frac{18}{20}\)
Now substitute this back into the equation for A:
\(A = \frac{18}{20} - \frac{3}{20}\)
\(A = \frac{18 - 3}{20}\)
\(A = \frac{15}{20}\)
We can simplify the fraction for A by dividing both the numerator and denominator by their greatest common divisor, which is 5:
\(A = \frac{15 \div 5}{20 \div 5} = \frac{3}{4}\)
So, the value of fraction A is \(\frac{3}{4}\).
We know that the sum of A, B, and C is \(\frac{121}{60}\). Substitute the value of A we just found:
\(\frac{3}{4} + B + C = \frac{121}{60}\)
We also know that C divided by B is \(\frac{9}{10}\). This can be written as:
\(\frac{C}{B} = \frac{9}{10}\)
We can rearrange this equation to express C in terms of B:
\(C = \frac{9}{10} \times B\)
Now substitute the expression for C (\(C = \frac{9}{10} B\)) into the sum equation:
\(\frac{3}{4} + B + \frac{9}{10} B = \frac{121}{60}\)
Combine the terms involving B. Note that \(B = 1 \times B = \frac{10}{10} B\):
\(\frac{3}{4} + \left(1 + \frac{9}{10}\right) B = \frac{121}{60}\)
\(\frac{3}{4} + \left(\frac{10}{10} + \frac{9}{10}\right) B = \frac{121}{60}\)
\(\frac{3}{4} + \frac{19}{10} B = \frac{121}{60}\)
Now, isolate the term with B by subtracting \(\frac{3}{4}\) from both sides:
\(\frac{19}{10} B = \frac{121}{60} - \frac{3}{4}\)
Find a common denominator for the right side, which is 60. Convert \(\frac{3}{4}\) to an equivalent fraction with a denominator of 60:
\(\frac{3}{4} = \frac{3 \times 15}{4 \times 15} = \frac{45}{60}\)
Substitute this back into the equation:
\(\frac{19}{10} B = \frac{121}{60} - \frac{45}{60}\)
\(\frac{19}{10} B = \frac{121 - 45}{60}\)
\(\frac{19}{10} B = \frac{76}{60}\)
To solve for B, multiply both sides by \(\frac{10}{19}\):
\(B = \frac{76}{60} \times \frac{10}{19}\)
We can simplify before multiplying. Note that 76 is \(19 \times 4\) and 60 is \(6 \times 10\).
\(B = \frac{4 \times 19}{6 \times 10} \times \frac{10}{19}\)
Cancel out the common factors 19 and 10:
\(B = \frac{4}{6}\)
Simplify the fraction for B:
\(B = \frac{4 \div 2}{6 \div 2} = \frac{2}{3}\)
So, the value of fraction B is \(\frac{2}{3}\).
We use the relationship \(C = \frac{9}{10} B\) and the value of B we just found:
\(C = \frac{9}{10} \times \frac{2}{3}\)
Multiply the numerators and the denominators:
\(C = \frac{9 \times 2}{10 \times 3}\)
\(C = \frac{18}{30}\)
Simplify the fraction for C by dividing both the numerator and denominator by their greatest common divisor, which is 6:
\(C = \frac{18 \div 6}{30 \div 6} = \frac{3}{5}\)
So, the value of fraction C is \(\frac{3}{5}\).
The question asks for the difference between B and C, which is \(B - C\). We have the values for B and C:
\(B = \frac{2}{3}\) and \(C = \frac{3}{5}\)
Calculate the difference:
\(B - C = \frac{2}{3} - \frac{3}{5}\)
To subtract these fractions, find a common denominator, which is 15. Convert both fractions to equivalent fractions with a denominator of 15:
\(\frac{2}{3} = \frac{2 \times 5}{3 \times 5} = \frac{10}{15}\)
\(\frac{3}{5} = \frac{3 \times 3}{5 \times 3} = \frac{9}{15}\)
Now substitute these back into the difference calculation:
\(B - C = \frac{10}{15} - \frac{9}{15}\)
\(B - C = \frac{10 - 9}{15}\)
\(B - C = \frac{1}{15}\)
The difference between B and C is \(\frac{1}{15}\).
Let's quickly check if A > B > C holds: A=\(\frac{3}{4}\) (0.75), B=\(\frac{2}{3}\) (\(\approx\) 0.667), C=\(\frac{3}{5}\) (0.6). Yes, \(0.75 > 0.667 > 0.6\).
| Fraction | Value | Decimal Approx |
|---|---|---|
| A | \(\frac{3}{4}\) | 0.75 |
| B | \(\frac{2}{3}\) | 0.666... |
| C | \(\frac{3}{5}\) | 0.6 |
The difference between B and C is \(\frac{1}{15}\).
| Concept | Description | Example |
|---|---|---|
| Adding/Subtracting Fractions | Find a common denominator, convert fractions, then add/subtract numerators. | \(\frac{1}{2} + \frac{1}{3} = \frac{3}{6} + \frac{2}{6} = \frac{5}{6}\) |
| Multiplying Fractions | Multiply numerators together and denominators together. Simplify if possible. | \(\frac{2}{3} \times \frac{3}{4} = \frac{6}{12} = \frac{1}{2}\) |
| Dividing Fractions | Multiply the first fraction by the reciprocal of the second fraction. | \(\frac{1}{2} \div \frac{1}{4} = \frac{1}{2} \times \frac{4}{1} = \frac{4}{2} = 2\) |
| Solving Equations with Fractions | Use inverse operations (addition/subtraction, multiplication/division) to isolate the variable. Find common denominators when adding/subtracting terms. | If \(x + \frac{1}{4} = \frac{3}{4}\), then \(x = \frac{3}{4} - \frac{1}{4} = \frac{2}{4} = \frac{1}{2}\) |
Fractions represent parts of a whole. They consist of a numerator (the top number) and a denominator (the bottom number). The denominator indicates the total number of equal parts the whole is divided into, and the numerator indicates how many of those parts are being considered.
Key concepts when working with fractions:
Solving word problems involving fractions often requires translating the problem's sentences into mathematical equations and then using algebraic techniques to solve for the unknown values, as demonstrated in this problem.
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