The sum of the present ages of a father and his son is 60 years. Six years ago, father’s age was five times the age of the son. After 6 years, son’s age will be:
20 years
The question asks us to find the son's age after 6 years, given the sum of the present ages of the father and son, and a relationship between their ages six years ago.
Let's use variables to represent their current ages:
From the question, we have two pieces of information that can be translated into equations:
Now we have a system of two linear equations with two variables:
\(F + S = 60\)
\(F - 6 = 5(S - 6)\)
We can solve this system using substitution. From Equation 1, we can express \(F\) in terms of \(S\):
\(F = 60 - S\)
Now, substitute this expression for \(F\) into Equation 2:
\((60 - S) - 6 = 5(S - 6)\)
Simplify the left side:
\(54 - S = 5(S - 6)\)
Distribute the 5 on the right side:
\(54 - S = 5S - 30\)
Now, we need to isolate \(S\). Let's move all terms with \(S\) to one side and constant terms to the other side. Add \(S\) to both sides and add 30 to both sides:
\(54 + 30 = 5S + S\)
\(84 = 6S\)
Now, divide by 6 to find the value of \(S\):
\(S = \frac{84}{6}\)
\(S = 14\)
So, the present age of the son is 14 years.
The question asks for the son's age after 6 years.
Son's age after 6 years = Present age of son + 6 years
Son's age after 6 years = \(14 + 6\)
Son's age after 6 years = \(20\) years
Therefore, the son's age will be 20 years after 6 years.
Let's quickly check if these ages satisfy the original conditions.
Present ages: Son = 14, Father = 60 - 14 = 46.
Sum of present ages: \(46 + 14 = 60\). This matches the first condition.
Ages six years ago: Son = \(14 - 6 = 8\), Father = \(46 - 6 = 40\).
Was father's age five times the son's age six years ago? \(5 \times 8 = 40\). Yes, \(40 = 5 \times 8\). This matches the second condition.
The calculated present ages are correct, and the son's age after 6 years is 20.
| Concept | Explanation | How it's used here |
|---|---|---|
| Present Age | The age of a person at the current time. | Represented by variables \(F\) and \(S\). |
| Age in the Past | Age at a time \(x\) years ago. Calculated as Present Age \( - x\). | Father's age 6 years ago: \(F - 6\). Son's age 6 years ago: \(S - 6\). |
| Age in the Future | Age at a time \(y\) years from now. Calculated as Present Age \( + y\). | Son's age 6 years from now: Present Son Age \( + 6\). |
| Forming Equations | Translating relationships given in the problem into mathematical equations. | Sum of ages: \(F + S = 60\). Past relationship: \(F - 6 = 5(S - 6)\). |
| Solving Simultaneous Equations | Finding the values of variables that satisfy all given equations. Methods include substitution or elimination. | We used substitution to find \(S\) and \(F\). |
Age problems are a common type of word problem in algebra. Here are some general strategies:
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Present ages of Sai and Satheesh are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Satheesh’s present age in years?
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Ram’s father is twice as old as Ram is. Eight years ago, the age of Ram’s father was 2.5 times his age. What is Ram’s current age?
The ages of two persons P and Q are in the ratio 5 : 7. Eight years ago, the ratio of P and Q was 7 : 13. The present ages of P and Q, respectively, are:
One year ago, the ratio of the ages of A and B was 4 : 3. The ratio of their ages, after 7 years from now, will be 9 : 7. What is the present age (in years) of B?
In 8 years, Subhash will be 3 times as old as he is now. After how many years will Subhash be 5 times as old as he is now?
The average ages of parents and two children are 30 years and 8 years respectively. The average age of the family is
A. 16 years
B. 19 years
C. 18 years
D. 17 years
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