5 years ago, my sister's age was 5 times my age. Now it is 3 times only. What is my sister's present age (in years)?
30
This problem requires us to find the sister's current age based on the relationship between her age and my age at two different times: 5 years ago and the present.
To solve this, let's define variables for our current ages:
M represent my current age (in years).S represent my sister's current age (in years).We can translate the information given in the problem into mathematical equations:
Five years ago, my age was M - 5 and my sister's age was S - 5.
The problem states: "my sister's age was 5 times my age". This gives us the equation:
$$ S - 5 = 5 \times (M - 5) $$
Let's simplify this equation:
$$ S - 5 = 5M - 25 $$
Rearranging to express S in terms of M:
$$ S = 5M - 25 + 5 $$
$$ S = 5M - 20 $$ (This is our Equation 1)
The problem states: "Now it is 3 times only". This means the sister's current age is 3 times my current age.
$$ S = 3M $$ (This is our Equation 2)
We now have two equations for S. We can find the ages by solving this system. A good method is substitution. Since Equation 2 tells us S = 3M, we can substitute 3M for S in Equation 1:
Substitute 3M into Equation 1:
$$ 3M = 5M - 20 $$
Now, let's solve for M:
Subtract 3M from both sides:
$$ 0 = 5M - 3M - 20 $$
$$ 0 = 2M - 20 $$
Add 20 to both sides:
$$ 20 = 2M $$
Divide by 2:
$$ M = \frac{20}{2} $$
$$ M = 10 $$
This means my current age is 10 years.
We need to find the sister's present age, S. We can use Equation 2:
$$ S = 3M $$
Substitute the value we found for M (which is 10):
$$ S = 3 \times 10 $$
$$ S = 30 $$
So, the sister's present age is 30 years.
Let's check our answer using the condition from 5 years ago:
10 - 5 = 5 years.30 - 5 = 25 years.25 = 5 \times 5.The calculations confirm that the sister's present age is 30 years.
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