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The sum of all the elements in the range of $f(x) = \text{Sgn}(\sin x) + \text{Sgn}(\cos x) + \text{Sgn}(\tan x) + \text{Sgn}(\cot x)$,
$x \neq \frac{n\pi}{2}, n \in \mathbf{Z}$, where $\text{Sgn}(t) = \begin{cases} 1, & \text{if } t > 0 \\ -1, & \text{if } t < 0 \end{cases}$, is :

The correct answer is
$0$

The problem asks for the sum of all elements in the range of the function $f(x) = \text{Sgn}(\sin x) + \text{Sgn}(\cos x) + \text{Sgn}(\tan x) + \text{Sgn}(\cot x)$, where $x \neq \frac{n\pi}{2}$ for any integer $n$. The Signum function, $\text{Sgn}(t)$, returns $1$ if $t > 0$ and $-1$ if $t < 0$. The condition $x \neq \frac{n\pi}{2}$ excludes angles where the trigonometric functions are zero or undefined.

Evaluating Trigonometric Signs by Quadrant

We need to determine the signs of $\sin x$, $\cos x$, $\tan x$, and $\cot x$ in each of the four quadrants.

Quadrant I: $0 < x < \frac{\pi}{2}$

  • $\sin x > 0 \implies \text{Sgn}(\sin x) = 1$
  • $\cos x > 0 \implies \text{Sgn}(\cos x) = 1$
  • $\tan x = \frac{\sin x}{\cos x} > 0 \implies \text{Sgn}(\tan x) = 1$
  • $\cot x = \frac{\cos x}{\sin x} > 0 \implies \text{Sgn}(\cot x) = 1$

For Quadrant I, $f(x) = 1 + 1 + 1 + 1 = 4$.

Quadrant II: $\frac{\pi}{2} < x < \pi$

  • $\sin x > 0 \implies \text{Sgn}(\sin x) = 1$
  • $\cos x < 0 \implies \text{Sgn}(\cos x) = -1$
  • $\tan x = \frac{\sin x}{\cos x} < 0 \implies \text{Sgn}(\tan x) = -1$
  • $\cot x = \frac{\cos x}{\sin x} < 0 \implies \text{Sgn}(\cot x) = -1$

For Quadrant II, $f(x) = 1 + (-1) + (-1) + (-1) = -2$.

Quadrant III: $\pi < x < \frac{3\pi}{2}$

  • $\sin x < 0 \implies \text{Sgn}(\sin x) = -1$
  • $\cos x < 0 \implies \text{Sgn}(\cos x) = -1$
  • $\tan x = \frac{\sin x}{\cos x} > 0 \implies \text{Sgn}(\tan x) = 1$
  • $\cot x = \frac{\cos x}{\sin x} > 0 \implies \text{Sgn}(\cot x) = 1$

For Quadrant III, $f(x) = (-1) + (-1) + 1 + 1 = 0$.

Quadrant IV: $\frac{3\pi}{2} < x < 2\pi$

  • $\sin x < 0 \implies \text{Sgn}(\sin x) = -1$
  • $\cos x > 0 \implies \text{Sgn}(\cos x) = 1$
  • $\tan x = \frac{\sin x}{\cos x} < 0 \implies \text{Sgn}(\tan x) = -1$
  • $\cot x = \frac{\cos x}{\sin x} < 0 \implies \text{Sgn}(\cot x) = -1$

For Quadrant IV, $f(x) = (-1) + 1 + (-1) + (-1) = -2$.

Summing Range Elements

The function $f(x)$ can take the values $4, -2, 0, -2$ depending on the quadrant. The question asks for the sum of "all the elements in the range". Interpreting this as the sum of the values obtained across the four representative intervals (quadrants):

Sum = (Value in Q1) + (Value in Q2) + (Value in Q3) + (Value in Q4)

Sum = $4 + (-2) + 0 + (-2)$

Sum = $4 - 2 + 0 - 2 = 0$.

Thus, the sum of all the elements in the range is $0$.

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