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Question

The structures of the major products W and X in the following synthetic scheme are 

The correct answer is

Let's analyze the reaction scheme step-by-step to determine the structures of the major products W and X.

  1. The first step involves the reaction of pyridine with \text{CH}_3\text{CO}_3\text{H} (peracetic acid). This is an example of an oxidation reaction, where pyridine is oxidized to form pyridine N-oxide. This reaction involves the addition of an oxygen atom to the nitrogen in pyridine, leading to the formation of product W, pyridine N-oxide.

  2. In the second step, the N-oxide (W) is reacted with benzyl bromide followed by NaOH. This is a nucleophilic substitution reaction where the N-oxide acts as a nucleophile. The N(-O) group attacks the benzyl carbon, displacing the bromide ion. The base (NaOH) deprotonates and stabilizes the intermediate, leading to the formation of product X, which is a benzylated pyridine N-oxide.

From the given options, the structures correspond to the following major products:

  • Product W: Pyridine N-oxide.
  • Product X: Benzylated pyridine N-oxide (Benzyl group attached via the oxygen of N-oxide).

The correct structure for the major products W and X is shown in one of the images provided with the options.

Therefore, the correct answer is the structure corresponding to the product X having a benzyl group attached to the N-oxide of pyridine.

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Important Questions from Heterocyclic Chemistry

  1. The major product formed in the following reaction sequences is

  2. The reaction(s) that yield(s) 2-methylquinoline as the major product is (are)
  3. Which one of the following bioreactor configurations is the basis for a trickling biological filter?
  4. The major products M and N formed in the following reactions are

  5. An enzyme converts substrate A to product B. At a given liquid feed stream of flow rate $25 \ L.min^{-1}$ and feed substrate concentration of $2 \ mol.L^{-1}$, the volume of continuous stirred tank reactor needed for 95% conversion will be ____________________ L. 

    Given the rate equation: $-r_A = \frac{0.1C_A}{1+0.5C_A}$ 

    where $-r_A$ is the rate of reaction in $mol.L^{-1}.min^{-1}$ and $C_A$ is the substrate concentration in $mol.L^{-1}$ 

    Assumptions: Enzyme concentration is contant and does not undergo any deactivation during the reaction.

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