The problem asks us to find the smallest number, let's call it \(x\), that can be added to 56789 to make the sum divisible by 345. After finding \(x\), we need to calculate the sum of its digits.
First, we divide 56789 by 345 to find the remainder.
Using division: \(56789 \div 345\)
\(56789 = 345 \times 164 + 209\)
The remainder when 56789 is divided by 345 is 209.
To make the number 56789 divisible by 345, we need to add a number that completes the next multiple of 345. The current remainder is 209. The amount needed to reach the next multiple of 345 is calculated as:
\(x = \text{Divisor} - \text{Remainder}\)
\(x = 345 - 209\)
\(x = 136\)
So, the smallest number \(x\) that can be added is 136.
Finally, we need to find the sum of the digits of \(x\).
\(x = 136\)
Sum of digits = \(1 + 3 + 6 = 10\).
The sum of the digits of \(x\) is 10.
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Consider all 3-digit numbers (without repetition of digits) obtained using three non-zero digits which are multiples of 3. Let S be their sum.
Which of the following is/are correct?
1. S is always divisible by 74.
2. S is always divisible by 9.
select the correct answer using the code given below: