Finding the Greatest 4-Digit Number
The largest 4-digit number is 9999.
To find the greatest 4-digit number divisible by 237, we divide 9999 by 237 and find the remainder.
Calculation:
\(9999 \div 237 \approx 42.19\)
Multiply the integer part of the quotient (42) by the divisor (237):
\(42 \times 237 = 9954\)
This value, 9954, is the greatest 4-digit number that is exactly divisible by 237.
Calculating the Sum of Digits
The digits of the number 9954 are 9, 9, 5, and 4.
We need to find the sum of these digits:
Sum = \(9 + 9 + 5 + 4\)
Sum = $ 27 $
The sum of the digits of the greatest 4-digit number divisible by 237 is 27.
Similar Questions
- Find the four-digit dividend of 21, 42, 147 and 105 that will give the remainder 14, 35, 140 and 98, respectively.
- The smallest number that can be added to 56789 to make it divisible by 345 is x. What is the sum of the digits of x?
- For which value of k number 345k6 is divisible by 3
- The smallest number that can be added to 56789 to make it divisible by 345 is x. What is the sum of the digits of x?
Important Questions from Divisibility and Remainder
If the 8-digit number 888x53y4 is divisible by 72, then what is the value of (7x + 2y), for the maximum value of y?
If all positive divisors of 132 are arranged in descending order, then what digit will be at unit place of first divisor ?
If 3 2019 is divided by 10, then what is the remainder?
The number 3798125P369 is divisible by 7. What is the value of the digit P?
Consider all 3-digit numbers (without repetition of digits) obtained using three non-zero digits which are multiples of 3. Let S be their sum.
Which of the following is/are correct?
1. S is always divisible by 74.
2. S is always divisible by 9.
select the correct answer using the code given below:
