Gift Article Price Ratio Problem
Let the prices of the three gift articles be \(2x\), \(5x\), and \(8x\), according to the given ratio 2 : 5 : 8.
Calculating the Price Multiplier
- The difference between the prices of the second and third articles is given as ₹5,055.
- In terms of the ratio multiplier \(x\), this difference is \(8x - 5x\).
- Set up the equation: \(8x - 5x = 5055\)
- Simplify the equation: \(3x = 5055\)
- Solve for \(x\): \(x = \frac{5055}{3}\) \(x = 1685\)
Finding the Sum of Prices
- The sum of the prices of the three articles is \(2x + 5x + 8x\).
- Combine the terms: \(Sum = (2 + 5 + 8)x\) \(Sum = 15x\)
- Substitute the value of \(x\) found earlier (\(x=1685\)): \(Sum = 15 \times 1685\)
- Calculate the final sum: \(Sum = 25275\)
Therefore, the sum of the prices of the three gift articles is ₹25,275.
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A sum of Rs. 2,500 is distributed among X, Y and Z in the ratio 1/2 : 3/4 : 5/6 . What is the difference between the maximum share and the minimum share?
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How many different sums can be formed with the denominations Rs. 50, Rs. 100, Rs. 200, Rs. 500 and Rs. 2,000 taking at least three denominations at a time?
In a 500 metres race, B starts 45 metres ahead of A, but A wins the race while B is still 35 metres behind. What is the ratio of the speeds of A to B assuming that both start at the same time?
The monthly incomes of Peter and Paul are in the ratio of 4 : 3. Their expenses are in the ratio of 3 : 2. If each saves Rs. 6,000 at the end of the month, their monthly incomes respectively are (in Rs.)
