Solving for the Three-Digit Number's Digit Sum
Finding the Digits
We are given that the product of the three digits of a number is 70. Let the digits be $a$, $b$, and $c$. We need to find three single digits (from 1 to 9, as a zero digit would make the product zero) such that $a \times b \times c = 70$.
First, find the prime factorization of 70:
$70 = 2 \times 5 \times 7$
Since 2, 5, and 7 are all single digits, these are the digits of the three-digit number. The order doesn't matter for finding the sum.
Calculating the Sum
The question asks for the sum of these digits. Calculate the sum:
Sum = $2 + 5 + 7$
Sum = $14$
The sum of the digits is 14. This matches Option B.
Important Questions from Numerical Relations
- $X$ and $Y$ are two positive real numbers such that $2X + Y \le 6$ and $X + 2Y \le 8$. For which of the following values of $(X, Y)$ the function $f(X, Y) = 3X + 6Y$ will give maximum value?
- If $3 \le X \le 5$ and $8 \le Y \le 11$ then which of the following options is TRUE?
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